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Let N be the no ...

such that N= ap . bq . cr

therefore the sum of the Factors of N = (ap+1 - 1)(bq+1 -1)(cr+1 - 1)/(a-1)(b-1)(c-1)

I hope this solves your problem :-) take care ...

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15y ago

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Q: Sum of factors of a number?
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