Wiki User
∙ 14y agoKing of Hearts (1/52)x Queen of Hearts (1/51)=1/2652
Wiki User
∙ 14y ago4/27
answer = 1 - probability you do get two green* * = binominal distribution f(k;n,p) = f(2;2,1/4)
The answer depends on how many cards are picked and whether or not the cards are replaced before picking the next one. If only three cards are picked and they are not replaced, the probability is 3*2*1/(52*51*50) = 1/22100 = 0.000 045 2 If the cards are replace, the probability is 3*2*1/523 = 0.000 042 7
The chance of picking a 2 is 4/52 since there are four twos. If you don't replace it then there are 51 cards and 4 sevens so the chance of picking the 7 is 4/51. The chances of doing both things is (4/52)(4/51)=16/2652 or 4/663 which is about .006
There are 9+6 = 15 checkers in the bag. 6 of them are red. 6 out of 15 are red. Drawing a red checker has a probability of P = 6/15 = 2/5 = 0.4 = 40% Since you replace the checker, the probability Q that red is drawn again remains 0.4. The probability of both events occurring (red drawn twice) equals the product of probabilities, PQ = (0.4)*(0.4) = 0.16.
This problem is the type of the probability of A and the probability of B. These events are independent. P(A) and P(B) = P(A) * P(B). In this case these two probabilities are equal; the probability of a king is 4/52. So, the probability of draw king, replace and draw king is 4/52 * 4/52 = 0.00592.
4/27
1-221
In the first two draws, the probability is 1/15.
yes
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They are independent, because the probability of the first event does not affect the probability of the second event.
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The answer is dependent on whether of not you replace the marbles in the jar. If you do, the probability of drawing a red marble is 9 in 15 or 60%, every time. If you do not replace the marbles, the probability of drawing a red marble is 2 in 8 or 25%.