answer = 1 - probability you do get two green*
* = binominal distribution f(k;n,p) = f(2;2,1/4)
the probability is you'd get a green marble any other color is impossible. So, the probability is certain
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
Assuming you replace the cube each time its drawn... 1/2 x 1/2 x 1/2 = 1/8
We can't answer that without knowing what else is in the bowl.
100%
the probability is you'd get a green marble any other color is impossible. So, the probability is certain
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
The probability is 0.625
To calculate the probability of not drawing two green marbles, we first find the probability of drawing a green marble on the first draw, which is 5/20 since there are 5 green marbles out of a total of 20 marbles. The probability of not drawing a green marble on the first draw is 1 - 5/20 = 15/20. Since the marbles are replaced, the probability of not drawing a green marble on the second draw is also 15/20. Therefore, the probability of not drawing two green marbles is (15/20) * (15/20) = 225/400 = 9/16 or 56.25%.
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
About a 74% estimated probability of green,
There are 16 marbles total and 7 green ones, so the probability is 7/16.
You find out how many choices there are in a spinner and then you take what it wants you to find the probability of and tur it into a fraction For example: You have a spinner with 4 triangles in it....2 are red and 2 are green,What is the probability of landing on a green triangle 2 out of 4
This is a law of addition probability which states that the probability of A or B equals the probability of A plus the probability of B minus the probability of A and B. Written in mathematical terms, the equation is: P(AorB) = P(A) + P(B) - P(AnB) where P(AnB) = 0 (since you can not pull out a green and black ball at the same time). Let P(A) = Probability of drawing the green ball & let P(B) = Probability of drawing the black ball. Total outcomes is 17. So, P(A) = 4/17 & P(B) = 6/17. Therefore P(green or black) = 4/17 + 6/17 = 10/17.
Assuming you replace the cube each time its drawn... 1/2 x 1/2 x 1/2 = 1/8
1
The probability that, if I get caught by a red light at one set of traffic lights, I will get a green at the next lights is an example.