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Q: Tan 90 degree
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What is tan x degree 90?

To solve for tan x degree 90 you do a few things. First, if x equals 90, then this equals 1.5597 radian or 89.36 degrees. This is the easiest way to solve tan x degree 90.


Why tan A 90 degree is not solve?

I am not sure what "tan A 90 degree" means. tan(90 degrees) is an expression that is not defined and so cannot be solved. One way to see why that may be so is to think of tan(x) = sin(x)/cos(x). When x = 90 degrees, sin(90) = 1 and cos(90)= 0 that tan(90) = 1/0 and since division by 0 is not defined, tan(90) is not defined.


How find the 90 degree elbow center?

How to calculate 90 degree and 40 degree elbow center >For 90 degree elbow(Dia*38.1) this formula used for only 90 degree elbow. >For 45 degree elbow(45/2of tan*Dia*1.5*25.4) this answer obtained in (mm).


What is the value of tan -90?

Assuming you mean -90 degrees, not radians: tan (-90) = [sin(-90)]/[cos(-90)] = (-1) / 0 You cannot divide by zero. tan (-90) is undefined/does not exist.


How do you get the center of elbow?

Formula for calculating center to end distance of such elbows is as follows: For 90° Long Radius elbows, center to end dimension given in dimension tables of ASME B16.9 is same as radius of elbow. This is because Tan (90/2) i.e. Tan 45 is 1. Normally custom elbow angles from 45 degree to 90 are cut from 90 degree standard elbow. If that's what you were asking about...


What angles form square angles?

90 degree angles.90 degree angles.90 degree angles.90 degree angles.


Why is tan90 equals infinity?

Note: Assuming you are working with natural, integer, rational(fraction), or real numbers. It doesn't. Infinity is not a number, even though, due to us mathematicians being lazy, we denote something = infinity. But we NEVER write tan 90 = infinity. But rather lim_x->(90degree) tan x = infinity. Meaning as x gets closer to 90 degree (even though degree is a horrible measurement for angle, we will use it), the value of tan x gets large faster and unbounded. tan x? It doesn't exist. Why? Because tan x is defined as (sin x / cos x). When x = 90 degree, cos x = 0, while sin x is positive around x = 90 degree. sin x / cos x := sinx x 1 / cos x, x = 90 degree, we get 1 x 1 / 0. But the definition for inverses does not include 0, meaning 1 / 0 does NOT exist. so, sadly, tan 90degree doesn't exist. The best we can do is see what happens around x = 90degree for tan, as you go into Calculus, you will know the tool is called limits and derivatives. And you might also see the reason it is +infinity, but not -infinity. (tan x approaches -infinity as x approaches 180degree). WHat's more? You will learn a far better measurement for angle that you will stick with in Calculus.


Hunter in a tree 90 ft above the ground see 2 deer. 1 is due west at at angle of depression 34 degrees and other due east at angle depression 58 degrees how far part to nearest whole number are they?

West. tan theta = opposite/adjacent you have opposite, 90 feet, you want adjacent ( degree mode) tan 34 degrees = 90 feet/adj. adjacent = 90 feet/tan 34 degrees = 133.4 feet ------------------------same for east tan 58 degrees = 90 feet/adj. adjacent = 90 feet/tan 58 degrees = 56.2 feet ------------------- 133.4 feet + 56.2 feet = 190 feet is the distance 2 deer are apart


In Triangle ABC what is the value of Tan A by 2 in terms of its sides if angle B is 90 degrees?

If B is 90 degrees, Tan A is BC / AB. But I don't know what you mean by Tan A by 2.


What country is 90 degrees north by 90 degrees east?

90 degree comes to poles.there is no living habitate in 90 degree N and 90 degree East


What is tan20tan32 plus tan32tan38 plus tan38tan20?

This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1


How do you convert slope percent into tan degree value?

Let m be the slope in percent and theta be the angle in question. tan (theta) = m/100 theta = arctan (m/100) To verify the result, we know the following: tan 0 = 0 tan (45 degrees) = 1 = 100% tan (90 degrees) = infinity For example, if 0 < m < 100%, then 0 < theta < 45 degrees.