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The midpoint of ab is m (-2, -4) if the coordinates of a are (-3, -5) what are the coordinates of B?
The coordinates of point B can be calculated using the midpoint formula. The midpoint formula is used to find the midpoint of two points, and is calculated by taking the average of the x-coordinates and the average of the y-coordinates.
In this case, we are given the midpoint of AB, which is (-2, -4). We also know the coordinates of point A, which are (-3, -5).
Using the midpoint formula, we can calculate the x-coordinate of point B by taking the average of the x-coordinates of points A and M. This is (-3 + -2)/2 = -2.5.
We can calculate the y-coordinate of point B in a similar way. This is (-5 + -4)/2 = -4.5.
Therefore, the coordinates of point B are (-2.5, -4.5).
What else can I help you with?
What is midpoint of AB if A has coordinates 45 and B has coordinates -2-3?
To find the midpoint of points A (45) and B (-2, -3), you can use the midpoint formula: ( M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ). Here, A seems to have only one coordinate, which might be a mistake. Assuming A is (45, 0), the midpoint would be ( M = \left( \frac{45 + (-2)}{2}, \frac{0 + (-3)}{2} \right) = \left( \frac{43}{2}, -\frac{3}{2} \right) ) or (21.5, -1.5).
The endpoints of a line segment graphed on a Cartesian coordinate system are -3 5 and 2 -1 What are the coordinates of the midpoint of the segment?
End points: (-3, 5) and 2, -1) Midpoint: (-3+2)/2 and (-1+5)/2 = (-1/2, 2)
How do you find an endpoint if you are given the other endpoint and the midpoint?
You practically just use the midpoint formula. M(x,y)= (x1 + x2, y1 + y2)---------- --------(the 2 is part of a fraction for the midpoint formula) ---> 2 2For ex.The midpoint of JK is (3,4). One endpoint is K(-3,-2).(-3 + y2 , -2 + y2).-------- ---------2 2You Multiply the midpoint coordinates to the denominators. So the midpoint coordinate 3 is multiplied to the first denominator and 4 is multiplied to the second denominator.The equations turn out to be:6=-3 + x2 AND 8= -2 + y2x2=9 y2=10so the Other endpoint's coordinates are (9,10)
What is the midpoint of a segment whose endpoints are (-3-3) and (-13-13)?
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
How do you solve the coordinate of A(35)are given.the midpoint is line AB is (-28).find the coordinate of B.?
If you mean end point A is (3, 5) and midpoint of line AB is (-2, 8) then end point B is (-7, 11)
M is the midpoint of line segment AB. A has coordinates (3-7) and M has coordinates (-11). What is the coordinates of B?
B is (-5, 9).
Find the length of AB and the coordinates of its midpoint Point A is plotted as -2X and 3Y Point B is plotted as 5X and -4Y?
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
If the midpoint of a horizontal line segment with a length of 8 is 3 -2 then the coordinates of its endpoints are?
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
What is the midpoint of AB if A is -3 and 12 and B is 21 and -8?
(9, 2)
What is the midpoint of the line segment with endpoints (1 7) and (3 3)?
Just calculate the midpoint (which is the same as the average) of both the x-coordinates and the y-coordinates.
The midpoint of the coordinates (9 11) and (7 8) is?
To find the midpoint, you find the mean (average) of each direction's coordinates. The average of the x coordinates is (9+7)/2 = 8. The average of y coordinates is (11+8)/2 = 9.5, So the midpoint is (8,9.5). This same method works for 3 and higher dimensions.
What is the midpoint of -23 and 8-7 coordinates?
If you mean: (-2, 3) and (8, -7) then the midpont is (3, -2)
M is the midpoint of JK The coordinates of J are 6 3 and the coordinates of M are -3 4 find the coordinates of K?
M is the midpoint and J and K are the endpoints.J has coordinates (6,3) and M has coordinates (-3,4) Let (x,y) be the coordinates of KThen ((6+x)/2, (3+y)/2)=(-3,4)So 1/2( 6+x)=-3 so 6+x=-6 and x=-121/2(3+y)=4 so 3+y=8 and y=5Then K=(-12,5)We check that M is in fact the midpoint of J=(6,3) and K=(-12,5)(-6/2, 8/2)=(-3,4)=M
The endpoints of a line segment graphed on a Cartesian coordinate system are -3 5 and 2 -1 What are the coordinates of the midpoint of the segment?
End points: (-3, 5) and 2, -1) Midpoint: (-3+2)/2 and (-1+5)/2 = (-1/2, 2)
How do you find an endpoint if you are given the other endpoint and the midpoint?
You practically just use the midpoint formula. M(x,y)= (x1 + x2, y1 + y2)---------- --------(the 2 is part of a fraction for the midpoint formula) ---> 2 2For ex.The midpoint of JK is (3,4). One endpoint is K(-3,-2).(-3 + y2 , -2 + y2).-------- ---------2 2You Multiply the midpoint coordinates to the denominators. So the midpoint coordinate 3 is multiplied to the first denominator and 4 is multiplied to the second denominator.The equations turn out to be:6=-3 + x2 AND 8= -2 + y2x2=9 y2=10so the Other endpoint's coordinates are (9,10)
What is the midpoint of a segment whose endpoints are (-3-3) and (-13-13)?
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
The endpoints of a segment are given Determine the midpoint of the segment if C 2 6 and D 4 0?
The midpoint formula is: [(x1 + x2)/2, (y1 + y2)/2]. If we denote the coordinates of the point C as (x1, y1) = (2, 6), and the coordinates of the point D as (x2, y2) = (4, 0), we can find the coordinates of the midpoint by using the above formula. So, [(x1 + x2)/2, (y1 + y2)/2] = [(2 + 4)/2, (6 + 0)/2] = (3, 3)
