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The midpoint of ab is m (-2, -4) if the coordinates of a are (-3, -5) what are the coordinates of B?
The coordinates of point B can be calculated using the midpoint formula. The midpoint formula is used to find the midpoint of two points, and is calculated by taking the average of the x-coordinates and the average of the y-coordinates.
In this case, we are given the midpoint of AB, which is (-2, -4). We also know the coordinates of point A, which are (-3, -5).
Using the midpoint formula, we can calculate the x-coordinate of point B by taking the average of the x-coordinates of points A and M. This is (-3 + -2)/2 = -2.5.
We can calculate the y-coordinate of point B in a similar way. This is (-5 + -4)/2 = -4.5.
Therefore, the coordinates of point B are (-2.5, -4.5).
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The endpoints of a line segment graphed on a Cartesian coordinate system are -3 5 and 2 -1 What are the coordinates of the midpoint of the segment?
End points: (-3, 5) and 2, -1) Midpoint: (-3+2)/2 and (-1+5)/2 = (-1/2, 2)
How do you find an endpoint if you are given the other endpoint and the midpoint?
You practically just use the midpoint formula. M(x,y)= (x1 + x2, y1 + y2)---------- --------(the 2 is part of a fraction for the midpoint formula) ---> 2 2For ex.The midpoint of JK is (3,4). One endpoint is K(-3,-2).(-3 + y2 , -2 + y2).-------- ---------2 2You Multiply the midpoint coordinates to the denominators. So the midpoint coordinate 3 is multiplied to the first denominator and 4 is multiplied to the second denominator.The equations turn out to be:6=-3 + x2 AND 8= -2 + y2x2=9 y2=10so the Other endpoint's coordinates are (9,10)
What is the midpoint of a segment whose endpoints are (-3-3) and (-13-13)?
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
How do you solve the coordinate of A(35)are given.the midpoint is line AB is (-28).find the coordinate of B.?
If you mean end point A is (3, 5) and midpoint of line AB is (-2, 8) then end point B is (-7, 11)
Find the diagonal of a square with sides measuring 6 units?
If the square has been plotted in a graph, you can go about finding the diagonal of it by measuring the midpoint. (1) Find the coordinates of the vertices of the square (2) Use the coordinates of two vertices that are across from each other. Plug them into the midpoint equation: (X1 + X2)/2 , (Y1 + Y2)/2, and use your answers as the coordinates of the midpoint (x,y) (3) Draw a straight line crossing through the midpoint from one opposite vertex to another. That is your diagonal.
M is the midpoint of line segment AB. A has coordinates (3-7) and M has coordinates (-11). What is the coordinates of B?
B is (-5, 9).
Find the length of AB and the coordinates of its midpoint Point A is plotted as -2X and 3Y Point B is plotted as 5X and -4Y?
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
If the midpoint of a horizontal line segment with a length of 8 is 3 -2 then the coordinates of its endpoints are?
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
What is the midpoint of AB if A is -3 and 12 and B is 21 and -8?
(9, 2)
What is the midpoint of the line segment with endpoints (1 7) and (3 3)?
Just calculate the midpoint (which is the same as the average) of both the x-coordinates and the y-coordinates.
The midpoint of the coordinates (9 11) and (7 8) is?
To find the midpoint, you find the mean (average) of each direction's coordinates. The average of the x coordinates is (9+7)/2 = 8. The average of y coordinates is (11+8)/2 = 9.5, So the midpoint is (8,9.5). This same method works for 3 and higher dimensions.
What is the midpoint of -23 and 8-7 coordinates?
If you mean: (-2, 3) and (8, -7) then the midpont is (3, -2)
M is the midpoint of JK The coordinates of J are 6 3 and the coordinates of M are -3 4 find the coordinates of K?
M is the midpoint and J and K are the endpoints.J has coordinates (6,3) and M has coordinates (-3,4) Let (x,y) be the coordinates of KThen ((6+x)/2, (3+y)/2)=(-3,4)So 1/2( 6+x)=-3 so 6+x=-6 and x=-121/2(3+y)=4 so 3+y=8 and y=5Then K=(-12,5)We check that M is in fact the midpoint of J=(6,3) and K=(-12,5)(-6/2, 8/2)=(-3,4)=M
The endpoints of a line segment graphed on a Cartesian coordinate system are -3 5 and 2 -1 What are the coordinates of the midpoint of the segment?
End points: (-3, 5) and 2, -1) Midpoint: (-3+2)/2 and (-1+5)/2 = (-1/2, 2)
How do you find an endpoint if you are given the other endpoint and the midpoint?
You practically just use the midpoint formula. M(x,y)= (x1 + x2, y1 + y2)---------- --------(the 2 is part of a fraction for the midpoint formula) ---> 2 2For ex.The midpoint of JK is (3,4). One endpoint is K(-3,-2).(-3 + y2 , -2 + y2).-------- ---------2 2You Multiply the midpoint coordinates to the denominators. So the midpoint coordinate 3 is multiplied to the first denominator and 4 is multiplied to the second denominator.The equations turn out to be:6=-3 + x2 AND 8= -2 + y2x2=9 y2=10so the Other endpoint's coordinates are (9,10)
What is the midpoint of a segment whose endpoints are (-3-3) and (-13-13)?
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
The endpoints of a segment are given Determine the midpoint of the segment if C 2 6 and D 4 0?
The midpoint formula is: [(x1 + x2)/2, (y1 + y2)/2]. If we denote the coordinates of the point C as (x1, y1) = (2, 6), and the coordinates of the point D as (x2, y2) = (4, 0), we can find the coordinates of the midpoint by using the above formula. So, [(x1 + x2)/2, (y1 + y2)/2] = [(2 + 4)/2, (6 + 0)/2] = (3, 3)
