9y
(6 * y) +9
To find two numbers where the difference is 9 and the product is 22, let’s denote the numbers as ( x ) and ( y ). We have the equations: ( x - y = 9 ) and ( x \cdot y = 22 ). Solving these, we can express ( x ) as ( y + 9 ) and substitute this into the product equation, leading to ( (y + 9) \cdot y = 22 ). This results in the quadratic equation ( y^2 + 9y - 22 = 0 ), which can be solved to find the values of ( x ) and ( y ).
9y + 7
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 9 ) and ( xy = 78 ). We can express ( y ) as ( y = 9 - x ) and substitute it into the product equation: ( x(9 - x) = 78 ). This simplifies to the quadratic equation ( x^2 - 9x + 78 = 0 ), which has solutions ( x = 6 ) and ( y = 3 ) (or vice versa), making the larger number 6.
The product of two consecutive numbers, where the smaller number is ( y ), can be expressed as ( y(y + 1) ). This is because the next consecutive number after ( y ) is ( y + 1 ). Therefore, the product is ( y^2 + y ).
(6 * y) +9
To find two numbers where the difference is 9 and the product is 22, let’s denote the numbers as ( x ) and ( y ). We have the equations: ( x - y = 9 ) and ( x \cdot y = 22 ). Solving these, we can express ( x ) as ( y + 9 ) and substitute this into the product equation, leading to ( (y + 9) \cdot y = 22 ). This results in the quadratic equation ( y^2 + 9y - 22 = 0 ), which can be solved to find the values of ( x ) and ( y ).
Oh, dude, that's like asking me to solve a math problem at a party. So, the expression "8 less than the product of y and 9" is just y times 9 minus 8. It's as simple as trying to find your friend's lost phone after a night out - a little annoying but not too complicated.
63 / 7 = 9. Therefore b = 9
9y + 7
xy = 20 x+y=9 x=9-y y(9-y) = 20 9y-y(squared) = 20 0= y(squared)-9y+20 0= (y-5)(y-4) y= 5 or 4, x= 5 or 4 The two numbers are 5 and 4.
that's impossibleAnswer:xy=9 and x+y=12reduces to the quadratic equation x2-12x+9=0so that once solvedx=-11.196 and y=-0.80385 (approx)
y=x+9 y'=1 x+9=0 x=-9 y=-9+9 y=0
Let's denote the two numbers as x and y. We know that x + y = 22 and x * y = 117. By solving these two equations simultaneously, we can find that the two numbers are 9 and 13. This is because 9 + 13 = 22 and 9 * 13 = 117.
The sum of x and y decreased by their product is (x + y)- xy.
The product of 5 and Y is simply the result of multiplying 5 by the value of Y. In mathematical terms, this can be represented as 5 * Y. The product will vary depending on the specific value assigned to Y.
y