Yes.
But note that if b2 - 4ac is negative, there are no real solutions to the quadratic equation to be found.
When complex numbers are used, this is not a problem as sqrt(-1) = i and so if b2 - 4ac is negative, "sqrt(b2 - 4ac)" becomes "i sqrt(4ac - b2)", meaning the solutions are:
x = -b/2a + i/2a sqrt(4ac-b2)
x = -b/2a - i/2a sqrt(4ac-b2)
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By using the quadratic equation formula
How you solve an equation that doesn't factor is to plug a quadratic equation's format; ax2+bx+c into the quadratic formula which is x=-b+square root to (b2-4ac)/2a.
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
With great difficulty because it is not a quadratic equation or even a quadratic expression.
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523