18" is not a possible perimeter measurement.
Assume the dimensions of the rectangle are so close to those of a square that the difference can be disregarded. This is the condition when the perimeter is at its minimum.
When the rectangle measures approximately 6" x 6", its area = 36 sq ins, its perimeter = 24"
For the area to remain constant then as the length increases by a factor n the width must decrease by that same factor.
Area = 6n x 6/n : perimeter = 12n + 12/n :so when n = 1, Perimeter = 12 + 12 = 24
As n increases, say n = 2, Perimeter = 24 + 6 = 30 : And the perimeter continues to increase as the rectangle becomes narrower. Eventually, it will become so narrow that
for diagram purposes it will appear as a straight line.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
yes
28 inches
The dimensions of the rectangle are 3 inches by 14 inches
10.5
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
yes
Perimeter:20 inches Area:35
28 inches
Perimeter = 24 inches Area = 35 square inches
Perimeter = 32 inches. Area = 55 square inches.
Yes it is possible. Consider these two shapes with the same area: a 2-inch square and a 1-inch x 4-inch rectangle both have the same area of 4 sq inches. However, the square has a perimeter of 8 inches while the rectangle has a perimeter of 10 inches. By the way, the shape with the largest area for a given perimeter is a circle.
If that's a rectangle, the perimeter is 24 inches and the area is 27 square inches.
The dimensions of the rectangle are 3 inches by 14 inches
24
10.5
3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches