If you mean the point (7, 9) then it is in the 1st quadrant
To find the image of the point (8, -9) after a dilation by a scale factor of 5 from the origin, we multiply each coordinate by 5. This gives us the new coordinates (8 * 5, -9 * 5) = (40, -45). If we then translate this point over the x-axis, we would change the y-coordinate to its opposite, resulting in the final coordinates (40, 45).
Yes.
To find the point that is 35% of the way from A(-9, 3) to B(21, -2), first calculate the vector from A to B: [ \text{Vector } AB = (21 - (-9), -2 - 3) = (30, -5). ] Next, multiply this vector by 0.35 to find the distance traveled from A: [ 0.35 \times (30, -5) = (10.5, -1.75). ] Now, add this to the coordinates of A: [ (-9, 3) + (10.5, -1.75) = (1.5, 1.25). ] Thus, the coordinates of the point are (1.5, 1.25).
Points: (6, -7) and (5, -9) Slope: 2
9
7
The coordinates are (10, 5).
If you mean the point (7, 9) then it is in the 1st quadrant
To find the image of the point (8, -9) after a dilation by a scale factor of 5 from the origin, we multiply each coordinate by 5. This gives us the new coordinates (8 * 5, -9 * 5) = (40, -45). If we then translate this point over the x-axis, we would change the y-coordinate to its opposite, resulting in the final coordinates (40, 45).
Yes.
To find the point that is 35% of the way from A(-9, 3) to B(21, -2), first calculate the vector from A to B: [ \text{Vector } AB = (21 - (-9), -2 - 3) = (30, -5). ] Next, multiply this vector by 0.35 to find the distance traveled from A: [ 0.35 \times (30, -5) = (10.5, -1.75). ] Now, add this to the coordinates of A: [ (-9, 3) + (10.5, -1.75) = (1.5, 1.25). ] Thus, the coordinates of the point are (1.5, 1.25).
If you mean points of (5, 8) and (3, 9) then the slope works out as -1/2
Divide the graph into 4 parts and each part is a quadrant. Traditionally, we use the x and y axis to divide it. The portion of the graph with positive x and y coordinates is the first quadrant, The second has positive y values and negative x values, while the third quadrant has both negative x and negative y values. The last is the fourth quadrants which is below the first quadrant. It has positive x values and negative y values. If you made the origin, the point (0,0) the center of a clock, the first quadrant is between 3 and 12 and the second between 12 and 9, the third between 9 and 6 and the fourth between 12 and 3.
B is (-5, 9).
quadrant 1
You cannot have a quadrant (a quarter) in a shape that is divided into 9 parts!