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The density of gold is 19.3 gcm The density of iron pyrite is 5.0 gcm a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
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What is the mass of a 10.0 cm3 sample of pyrite?
Pyrite has a density of 4.8-5g/cm3 mass = density x volume = (4.8-5)g/cm3 x 10 cm3 = 48 to 50 grams.
A nugget of gold with a mass of 521 g is added to 50.0 mL of water The water level rises to a volume of 77.0 mL What is the density of the gold?
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
Volume of air formula?
Volume = mass / Density Mass = Volume * Density Density = Mass / Volume
What are mathematical formulas to explain how mass volume and density are related?
Density = mass/volume Mass = (density) x (volume) Volume = mass/density
How do you calculate the volume in density?
density = mass/volume If you know density and mass, you can calculate the volume by manipulating the density equation such that volume = mass/density. Example: density = 3.57g/cm3 mass = 2.4g volume = ? volume = mass/density = 2.4g/3.57g/cm3 = 0.67cm3
The density of gold is 19.3 g cm3 The density of iron pyrite is 5.0 g cm3 If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
If a nugget of iron pyrite and a nugget of gold each have a mass of 50gwhat can you conclude about the volume of each nugget?
Since the density of gold is higher than that of iron pyrite, the gold nugget will have a smaller volume than the iron pyrite nugget. This is because for two materials with the same mass, the denser one will occupy less space.
If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
Since the mass of both nuggets is the same, the volume of the gold nugget will be smaller than the volume of the iron pyrite nugget. Gold is denser than iron pyrite, so it requires less volume to achieve the same mass.
Is a Nugget real gold or fools gold if a it has a mass of 100.0 g and displaces the water level in a graduated cylinder by 15.0cm3 from 10.0cm3?
To determine whether the nugget is real gold or fool's gold, you can calculate its density. The density of gold is 19.32 g/cm3, while the density of fool's gold (iron pyrite) is about 5 g/cm3. Based on the displacement of water and the mass provided, calculate the density of the nugget using the formula: density = mass/volume. Compare the calculated density to the known densities of gold and fool's gold to identify the material.
What is the mass of a piece of pyrite that has a volume of 10 ml?
The density of pyrite is about 5 g/cm³. To find the mass of the pyrite, you can use the formula: mass = density x volume. Therefore, in this case, the mass of the pyrite would be 50 grams.
What is the mass of a piece of pyrite that has a volume of 40cm3?
Iron pyrite (FeS2) has a density of 4.8 to 5.0 grams per cm3. A piece of volume 40 cm3 would, therefore have a mass of volume*density = 192 to 200 grams.
What is the density of a gold nugget that has a volume of 1.68 cm3 and a mass of 32.4 g?
With the information given, the density of your nugget is about 19.29 g/cc. The density of gold is given as about 19.3 g/cc, so your nugget fits the density requirements for it to be a gold nugget.
What is the density of a nugget of gold that has a mass of 965 g and a volume of 50 cm cubed?
The density of the gold nugget is 19.3 g/cm^3. This was calculated by dividing the mass (965 g) by the volume (50 cm^3).
An irregularly shaped gold nugget weighs 24.3g and is found to displace 1.26ml of water. Can it be determined if it is really gold?
Yes, the density of gold is known (19.32 g/cm^3). By using the formula for density (density = mass/volume), you can calculate the expected volume the gold nugget should displace based on its mass. If the calculated volume matches closely with the measured volume, it is likely the nugget is made of gold.
What is the mass of a 10.0 cm3 sample of pyrite?
Pyrite has a density of 4.8-5g/cm3 mass = density x volume = (4.8-5)g/cm3 x 10 cm3 = 48 to 50 grams.
What is the density of a piece of iron pyrite that has a mass of 57.2 g and a volume of 11 cm cubed?
Density = Mass/Volume = 57.2g/11 cm3 = 5.2 gcm-3
A nugget of gold with a mass of 521 g is added to 50.0 mL of water The water level rises to a volume of 77.0 mL What is the density of the gold?
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
