One answer is a kite.
They are perpendicular and one diagonal is bisected.
It can be but a square and a rhombus diagonals are also perpendicular and therefore intersect at 90 degrees and they too are both quadrilaterals.
Perpendicular and the one for which each endpoint touches only sides of equal length bisects the other.
The diagonals are perpendicular to one another. The shorter diagonal is bisected by the longer diagonal. The kite is symmetrical about the longer diagonal. The longer diagonal bisects the angles at each end of the diagonal.
One answer is a kite.
The diagonals of a kite are perpendicular, and one diagonal is bisected. ~
They are perpendicular and one diagonal is bisected.
It can be but a square and a rhombus diagonals are also perpendicular and therefore intersect at 90 degrees and they too are both quadrilaterals.
Perpendicular and the one for which each endpoint touches only sides of equal length bisects the other.
The diagonals are perpendicular to one another. The shorter diagonal is bisected by the longer diagonal. The kite is symmetrical about the longer diagonal. The longer diagonal bisects the angles at each end of the diagonal.
Oh, dude, you're asking about a kite! Yeah, a kite doesn't have rotational symmetry and its diagonals are not perpendicular. It's like that one shape that's just doing its own thing, not conforming to the norms of the quadrilateral world.
It could be a kite or an irregular quadrilateral.
True, the diagonals of a rhombus are perpendicular bisectors of one another.
No - only one of the diagonals bisects the angles of the shape.
If both pairs of opposite sides are parallel: A Rectangle, or a Square. If exactly one pair of opposite sides are parallel: An Isosceles Trapezoid. If it does not have parallel sides and one diagonal is the perpendicular bisector of the other: A Kite It is also possible that it does not have any parallel sides and neither diagonal is the perpendicular bisector of the other: A quadrilateral
One pair