78 + yz = yz + 78
(z + 1)(y + x)
The idea here is to transfer to the other side everything you don't need. x = yz yz = x (switching both sides) y = x/z (you divide both sides by z, since you want to get rid of the z on the left side).
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
y(z+x) + 4(x+z)
78 + yz = yz + 78
xz + x + yz + y = (x + y)(z + 1)
(z + 1)(y + x)
The idea here is to transfer to the other side everything you don't need. x = yz yz = x (switching both sides) y = x/z (you divide both sides by z, since you want to get rid of the z on the left side).
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
y(z+x) + 4(x+z)
y2 + 10z - 10y - yz = y2 - 10y - yz + 10z = y(y - 10) - z(y - 10) = (y - 10)(y - z)
x(vw + wy - yz)
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
6xyz(3x + 2y + z)
3x 3y + 6z = 12
-3y + z = 12