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How does the graph show that the quadratic is a function?
No vertical line will intersect the graph in more than one point. The fundamental flaw is that no graph can show that it does not happen beyond the domain of the graph.
How can a quadratic function have both a maximum and a minimum point?
A quadratic function can only have either a maximum or a minimum point, not both. The shape of the graph, which is a parabola, determines this: if the parabola opens upwards (the coefficient of the (x^2) term is positive), it has a minimum point; if it opens downwards (the coefficient is negative), it has a maximum point. Therefore, a quadratic function cannot exhibit both extreme values simultaneously.
If the graph of quadratic function x has a minimum point and intersects the axis of x at 4 and m If the axis of symmetry of the graph is x equal to 5 state the value m and hence state the function x?
...i need the answer to that too...
How do you get the points to graph a quadratic function?
The quadratic equation is y=ax^2 +bx +c. So, you substitute in the values of a, b, and c to the quadratic formula (x= -b +/- \|b^2-4ac all over 2a) in order to find the x value then, substitute in x to the quadratic equation and solve. You will have point (x,y) to graph
What is the value of y at a point on a quadratic graph when it crosses the x axis?
zero
