Let L equal the larger of the two integers and S the smaller. Then L=2S.
Also L-1/S=1/S. Starting with this second equation and solving for L results in L=2/S. Equating the two values of L produces 2/S=2S and 1/S=S. The solutions to this last equation are S=1 or S=-1.
If L is to be the larger of the two integers, then S must equal 1 and L must equal 2.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
x > 16
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An integer that is larger than zero.An integer that is larger than zero.An integer that is larger than zero.An integer that is larger than zero.
The sum will be a positive integer.It will be at least as large as double the smaller integer and at most as large as double the larger integer.
If the integer subtracted is smaller than or equal to the first integer, then the answer is positive. Otherwise, if the integer subtracted is larger, then the answer is negative.
The larger integer is 30. The smaller is 28.
The smaller integer is 6, the larger integer is 32
Divide the larger number by the smaller one. If the answer is an integer, the larger number is a multiple of the smaller.
Divide the smaller into the larger. If the quotient is an integer, the smaller is a factor of the larger.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
Divide the smaller number into the larger number. If the answer is not an integer, the smaller number is not a factor.
x > 16
positive times negative equals negative
No.A positive integer is always larger than a negative integer. In the case of two negative integers, the integer with the larger absolute value is actually smaller.
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An integer that is larger than zero.An integer that is larger than zero.An integer that is larger than zero.An integer that is larger than zero.