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The machine only takes dimes and quarters and it has 52 coins worth 8.95 how many of each domination of coins are contained?
Wiki User
∙ 14y ago
Given:
10d + 25q = 895 cents
d + q = 52 coins
Multiply everything in the second equasion by 10 (to get rid of the dimes).
10d + 10q = 520
Subtract this 3rd equation from the 1st equation:
10d + 25q = 895
10d + 10d = 520
Giving you: 15q = 375
Divide both sides by 15 and you get q = 25
This means you have 25 quarters ($6.25) and 27 dimes ($2.70)
CHECK: 25 quarters + 27 dimes = 52 coins (CORRECT)
$6.25 + $2.70 = $8.95 (CORRECT)
Wiki User
∙ 14y ago
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