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How many ccs in a 124 inch motor?
According to S&S a 234" motor is equivalent to 2030 CCs.
What is the mass of ten 12 kilogram?
Mass of ten 12 kilograms = 10*12 = 120 kilograms
What is relationship between atomic mass and average atomic mass?
The average atomic mass is the ratio of the average mass of one atom of an element to one twelfth of the mass of an atom of carbon-12. It is, the mass of an atom of the substance, rescaled so that carbon-12 would have a mass of 12.
How do you prepare an aqueous solution as a percentage?
percent by mass = (mass of solute) / (mass of solute + mass of solvent) x 100% Ex: if you need a 12% by mass solution of salt then the easiest way is to get 12 g salt and 88 g of water thus the total is 100 g. 12 / (12+88) x 100% = 12%
What is Carbon-12 atomic mass?
12. The number 12 refers to the atomic mass. More precisely, to the sum of neutrons + protons; but this is usually close to the atomic mass. In the case of carbon-12, it is exact, by definition.
What is the percent by mass of carbon in aceton C3H6O?
To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.
What is the mass in grams of 38.86 of acetone?
To find the mass of 38.86 moles of acetone, you need to multiply the number of moles by the molar mass of acetone, which is approximately 58.08 g/mol. Therefore, the mass of 38.86 moles of acetone is approximately 2261.11 grams.
What is the mass in grams of 28.40mL of acetone?
To find the mass of acetone, we need to know the density of acetone, which is 0.786 g/mL. Multiplying the volume (28.40 mL) by the density gives us the mass of acetone: 28.40 mL * 0.786 g/mL = 22.33 grams.
What is percent by mass of carbon in acetone C3H6O?
To calculate the percent by mass of carbon in acetone (C3H6O), first calculate the molar mass of carbon in acetone: 3(C) = 3(12.01 g/mol) = 36.03 g/mol. Then calculate the molar mass of acetone: (3(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol = 58.08 g/mol. Finally, divide the molar mass of carbon by the molar mass of acetone and multiply by 100 to get the percent by mass of carbon in acetone: (36.03 g/mol / 58.08 g/mol) x 100 ≈ 62.07%.
How many ccs are in 6 Tablespoons?
That is 90 cc.
What is the acetone concentration in ppm of a solution made by mixing 23.2 mg acetone with 2.000 L water?
To calculate the concentration of acetone in ppm (parts per million), you would first convert the mass of acetone to grams (23.2 mg = 0.0232 g). Then you would divide the mass of acetone by the total mass of the solution (0.0232 g acetone / 2000 g water) and multiply by 1,000,000 to convert to ppm. Therefore, the acetone concentration would be 11.6 ppm.
What is the mass in grams of 17.54mL of acetone?
You need to konw the density of acetone (propanone) The use the equation density = mass / volume d = m/v m = dv
What is the mass in grams of 28.62mL of acetone?
To find the mass of acetone, you need to know its density. The density of acetone is 0.79 g/mL. Multiply the volume (28.62 mL) by the density to get the mass in grams. Mass = Volume x Density = 28.62 mL x 0.79 g/mL = 22.58 grams.
What is the percent of acetone c3h6o?
Acetone (C3H6O) is composed of 63.64% carbon, 13.64% hydrogen, and 22.73% oxygen by mass.
What is the value in mL of 6.60g of acetone if the density is 7857?
To find the volume in mL, divide the mass of acetone by its density. Volume = mass / density = 6.60g / 7857 g/mL ≈ 0.00084 mL. Therefore, 6.60g of acetone has a volume of approximately 0.00084 mL.
What weighs more water or acetone?
Water weighs more than acetone. This is because water has a higher density than acetone, meaning that a given volume of water will have a greater mass compared to the same volume of acetone.
How many acetone molecules are in a bottle of acetone with a volume of 330 ml?
Assuming the density of acetone is 0.79 g/ml, and the molar mass of acetone is 58.08 g/mol, you can calculate the number of acetone molecules in 330 ml using Avogadro's number. This will give you approximately 6.69 x 10^23 molecules of acetone in a 330 ml bottle of acetone.
