Q: What is the mass in grams of 17.54mL of acetone?

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To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.

80 - 75 = 5 grams.

The mass is 295 grams. This is multiplication and subtraction. 9 x 238 = 2142 grams for the balls Total - ball mass = box mass 2437 - 2142 = 295 grams

500 grams

The mass of 40 grams is 40 grams and the volume of 20mL is, wait for it, ... 20 mL!

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To find the mass of acetone, we need to know the density of acetone, which is 0.786 g/mL. Multiplying the volume (28.40 mL) by the density gives us the mass of acetone: 28.40 mL * 0.786 g/mL = 22.33 grams.

To find the mass of 38.86 moles of acetone, you need to multiply the number of moles by the molar mass of acetone, which is approximately 58.08 g/mol. Therefore, the mass of 38.86 moles of acetone is approximately 2261.11 grams.

To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.

To find the mass of acetone, you need to know its density. The density of acetone is 0.79 g/mL. Multiply the volume (28.62 mL) by the density to get the mass in grams. Mass = Volume x Density = 28.62 mL x 0.79 g/mL = 22.58 grams.

To calculate the concentration of acetone in ppm (parts per million), you would first convert the mass of acetone to grams (23.2 mg = 0.0232 g). Then you would divide the mass of acetone by the total mass of the solution (0.0232 g acetone / 2000 g water) and multiply by 1,000,000 to convert to ppm. Therefore, the acetone concentration would be 11.6 ppm.

To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.

The molar mass of fingernail polish remover, which is typically acetone (CH3COCH3), is approximately 58 grams per mole.

To find the volume of a substance, you would need to know its density. The density of acetone is approximately 0.79 g/mL. Using this information, you can calculate the volume of 6.54 g of acetone by dividing the mass by the density (6.54 g / 0.79 g/mL = 8.27 mL).

To calculate the amount of acetone needed, we first need to find the molar mass of acetone, which is approximately 58.08 g/mol. Then, we can use the density to convert moles to grams: 3.35 moles * 58.08 g/mol = approximately 194.788 g. Finally, we can convert grams to volume using the density: 194.788 g / 0.851 g/mL ≈ 228.91 mL of acetone would be needed.

The density acetone is 0.79 g/cm3. So 12 cm3 has a mass of 9.48 g

To calculate the percent by mass of carbon in acetone (C3H6O), first calculate the molar mass of carbon in acetone: 3(C) = 3(12.01 g/mol) = 36.03 g/mol. Then calculate the molar mass of acetone: (3(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol = 58.08 g/mol. Finally, divide the molar mass of carbon by the molar mass of acetone and multiply by 100 to get the percent by mass of carbon in acetone: (36.03 g/mol / 58.08 g/mol) x 100 ≈ 62.07%.

The mass of 60 grams is 60 grams, the mass of 0 grams is 0 grams, and the mass of 2.2 grams is 2.2 grams.