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You need to konw the density of acetone (propanone)

The use the equation

density = mass / volume

d = m/v

m = dv

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lenpollock

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3w ago
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10y ago

With a density of 0.7857g/cm3, you have a mass of 13.78mL.

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Q: What is the mass in grams of 17.54mL of acetone?
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What is the mass in grams of 28.40mL of acetone?

To find the mass of acetone, we need to know the density of acetone, which is 0.786 g/mL. Multiplying the volume (28.40 mL) by the density gives us the mass of acetone: 28.40 mL * 0.786 g/mL = 22.33 grams.


What is the mass in grams of 38.86 of acetone?

To find the mass of 38.86 moles of acetone, you need to multiply the number of moles by the molar mass of acetone, which is approximately 58.08 g/mol. Therefore, the mass of 38.86 moles of acetone is approximately 2261.11 grams.


What is the Volume of 10 grams of acetone?

To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.


What is the mass in grams of 28.62mL of acetone?

To find the mass of acetone, you need to know its density. The density of acetone is 0.79 g/mL. Multiply the volume (28.62 mL) by the density to get the mass in grams. Mass = Volume x Density = 28.62 mL x 0.79 g/mL = 22.58 grams.


What is the acetone concentration in ppm of a solution made by mixing 23.2 mg acetone with 2.000 L water?

To calculate the concentration of acetone in ppm (parts per million), you would first convert the mass of acetone to grams (23.2 mg = 0.0232 g). Then you would divide the mass of acetone by the total mass of the solution (0.0232 g acetone / 2000 g water) and multiply by 1,000,000 to convert to ppm. Therefore, the acetone concentration would be 11.6 ppm.


What is the percent by mass of carbon in aceton C3H6O?

To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.


What is the molar mass of fingernail polish remover?

The molar mass of fingernail polish remover, which is typically acetone (CH3COCH3), is approximately 58 grams per mole.


What is the volume in ml of 6.54 g of acetone?

To find the volume of a substance, you would need to know its density. The density of acetone is approximately 0.79 g/mL. Using this information, you can calculate the volume of 6.54 g of acetone by dividing the mass by the density (6.54 g / 0.79 g/mL = 8.27 mL).


How much acetone (CH3COCH3) would be needed to obtain 3.35 moles of acetone The density of acetone is 0.851 gmL.?

To calculate the amount of acetone needed, we first need to find the molar mass of acetone, which is approximately 58.08 g/mol. Then, we can use the density to convert moles to grams: 3.35 moles * 58.08 g/mol = approximately 194.788 g. Finally, we can convert grams to volume using the density: 194.788 g / 0.851 g/mL ≈ 228.91 mL of acetone would be needed.


The mass of 12 cc's of acetone is?

The density acetone is 0.79 g/cm3. So 12 cm3 has a mass of 9.48 g


What is percent by mass of carbon in acetone C3H6O?

To calculate the percent by mass of carbon in acetone (C3H6O), first calculate the molar mass of carbon in acetone: 3(C) = 3(12.01 g/mol) = 36.03 g/mol. Then calculate the molar mass of acetone: (3(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol = 58.08 g/mol. Finally, divide the molar mass of carbon by the molar mass of acetone and multiply by 100 to get the percent by mass of carbon in acetone: (36.03 g/mol / 58.08 g/mol) x 100 ≈ 62.07%.


What is the mass of 60 grams 0 grams and 2.2 grams?

The mass of 60 grams is 60 grams, the mass of 0 grams is 0 grams, and the mass of 2.2 grams is 2.2 grams.