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∙ 14y ago2L + 2W = 980
3W - 30 = L
subsituting
2(3W - 30) + 2W = 980
6W - 60 + 2W = 980
8W = 1040
W = 130
3 x (130) - 30 = L
L = 360
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∙ 14y agoSince the dimensions of a standard football field are 105 x 68m, and a football field is a rectangle, then 105 + 68 + 105 + 68 = 346, so the perimeter is 346m.
The length is 10 meters and the width is 5 meters
Let the length be 2x+3 and the width be x: So: 2*(2x+3+x) = 258 => x = 42 feet Therefore: length = 87 feet and width = 42 feet Check: 2*(87+42) = 256 feet
The perimeter is 328 m. (Width: 64m length: 100m)
The least possible length of fence that can enclose 20 acres is 3,308.75 ft.That's if the field is circular.If the field is square, then it takes 3,733.5 ft.If it's a rectangle ... straight sides but not a square ... then the perimeter can beanything more than 3,733.5 ft, depending on the shape of the rectangle. The areadoesn't tell you what the perimeter has to be.
Since the dimensions of a standard football field are 105 x 68m, and a football field is a rectangle, then 105 + 68 + 105 + 68 = 346, so the perimeter is 346m.
The length is 10 meters and the width is 5 meters
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Let the length be 2x+3 and the width be x: So: 2*(2x+3+x) = 258 => x = 42 feet Therefore: length = 87 feet and width = 42 feet Check: 2*(87+42) = 256 feet
The length is 200 yards and the width is 48 yards.length + width = 248 yards, and length = (4 x width) + 8 yards.substituting (4 x width) + 8 yards for length,(4 x width) + 8 yards + width = 248 yards;simplifying, width = 240/5 yards = 48 yards;then length = 248 - 48 yards = 200 yards
The perimeter is 328 m. (Width: 64m length: 100m)
The least possible length of fence that can enclose 20 acres is 3,308.75 ft.That's if the field is circular.If the field is square, then it takes 3,733.5 ft.If it's a rectangle ... straight sides but not a square ... then the perimeter can beanything more than 3,733.5 ft, depending on the shape of the rectangle. The areadoesn't tell you what the perimeter has to be.
The area does not uniquely determine the linear dimensions of the boundary. The same area could be covered by many different shapes, with different dimensions. 1.5 hectares is 15,000 square meters. If the field is square, then the length of each side is about 122.5 meters, and the perimeter is about 489.9 meters. If the field is a circle, then its diameter is about 138.2 meters, and its perimeter (circumference) is about 434 meters. If the field is a triangle with 3 equal sides, then the side is about 186 meters, and the perimeter is about 558.4 meters. It could also be a rectangle measuring 150 by 100 (perimeter = 500), or 15 by 1,000 (perimeter = 2,030), or 5 by 3,000 (perimeter = 6,010), or many other choices. If you want to buy a piece of land and there's somebody willing to sell it to you by perimeter, buy a circle. It's the perimeter that covers the most area, and that means the most wheat or soybeans. Of course it also means the most property tax, and if you build on it, the most lawn to mow.
The answer may vary. If you take a square away from the field it will still have the same perimeter. So the Length and Width may vary on how you make the field.
Perimeter of a rectangle = 2x(l+b) = 2x(90+40)m = 2x130m = 260m.
Field = 5y x1y where y depicts the measurement and 5:1 is the ratio. The perimeter of the field = 325 yards, assuming that opposite sides of the field are of equal length. Therefore assume that the perimeter of the field = 1y+1y+5y+5y =12y Set 12y = 325 yards to get y=27.0833 yards Therefor the field is 135.4167 yards x 27.0833 yards.
you need to know the rectangle dimensions to determine this. Acres is area and is width x length. If it is long and thin you will need many poles as it could be very long. If it is a square since an acre is about 40,000 sq ft each side is 400 feet so perimeter is 1600 feet and you would need 1600/8 = 200 poles. If it is a rectangle 1600 x 100 feet perimeter is 3400 feet and you would need 3400/8 = 450 poles. If it is a rectangle 6400 x 25 feet perimeter is 12850 feet and you would need 12850/8 = 1607 poles, but the last two poles would only be 2 ft apart etc. Ask again and define the length or width of rectangle. ----------------------------------------------------------------------------------------------------------------- The perimeter of a rectangular area is any length greater than the minimum which is when the rectangle is a square. An area of 4 acres = 4 × 43560 ft² = 174240 ft² If this is a square, the side length is √174240 ft and it has a perimeter of 4 × √174240 ft = 528√10 ft ≈ 1670 ft. → you would need approx 1670 ft ÷ 8 ft/pole ≈ 208.7 poles → You will need at least 209 poles depending upon the exact dimensions of the rectangular 4 acres.