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The product of three consecutive integers is 210 What is the least of these integers?
Wiki User
∙ 14y ago
(x - 1)x(x + 1) = (x2 - 1)x = x3 - x = 210.
x3 - x - 210 = (x - 6)(x2 + 6x + 35) = 0
Thus, 6 = x (or -3 +- i*sqrt(26)). The real solution, 6, can be plugged back into x - 1 (the lowest), producing 5. 5 is your answer.
Wiki User
∙ 14y ago
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