its called the bounding box :P
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No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
parallelogram, rectangle, square -_-
Hi
A square or other shape drawn on paper that shows only the front profile (and not the sides) is a 2D plain figure.
a rhombus is a shape that looks like a diamond shape.... if you look up images on google and then type in rhombuses then it shows you some shapes that are rhombuses