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ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
ax2 + bx +c is an expression, not an equation. It cannot, therefore, have a solution. If the question concerns the equation ax2 + bx + c = 0 then the answer is ax2 - 16ax + 64a = 0 for any a other than 0.
ax2 + c = 0 Subtract c from both sides: ax2 = -c divide both sides by a: x2 = -c/a and so x = ± sqrt(-c/a) This has real solutions only if -c/a ≥ 0, that is, if c/a ≤ 0. Depending on the level you are at, if c/a ≥ 0 then there are the imaginary solutions i*sqrt(c/a).
any number
It's when ax2+bx+c=0 if b2-4ac= is negative