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What is a x squared plus b x plus c equals 0 in C programming?
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
What is the solution in standard form for ax2 plus bx plus c with only solution of 8?
ax2 + bx +c is an expression, not an equation. It cannot, therefore, have a solution. If the question concerns the equation ax2 + bx + c = 0 then the answer is ax2 - 16ax + 64a = 0 for any a other than 0.
How do you work out a problem like this ax squared plus c equals 0?
ax2 + c = 0 Subtract c from both sides: ax2 = -c divide both sides by a: x2 = -c/a and so x = ± sqrt(-c/a) This has real solutions only if -c/a ≥ 0, that is, if c/a ≤ 0. Depending on the level you are at, if c/a ≥ 0 then there are the imaginary solutions i*sqrt(c/a).
What is the value of a b and c in the equation ax2 plus bx plus c?
any number
When is there no real solutions for a quadratic equation?
It's when ax2+bx+c=0 if b2-4ac= is negative
Why are Quadratic equations which are expressed in the form of ax2 plus bx plus c 0 where a does not equal 0 may have how many solutions?
Why are Quadratic equations, which are expressed in the form of ax2 + bx + c = 0, where a does not equal 0,
What is a x squared plus b x plus c equals 0 in C programming?
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
What is the solution in standard form for ax2 plus bx plus c with only solution of 8?
ax2 + bx +c is an expression, not an equation. It cannot, therefore, have a solution. If the question concerns the equation ax2 + bx + c = 0 then the answer is ax2 - 16ax + 64a = 0 for any a other than 0.
How many solutions does a quadratic equation have when it is expressed in the form of ax2 plus bx plus c0 where a does not 0?
Assuming a, b, and c are real numbers, there are three possibilities for the solutions, depending on whether the discriminant - the square root part in the quadratic formula - is positive, zero, or negative:Two real solutionsOne ("double") real solutionTwo complex solutions
How do you work out a problem like this ax squared plus c equals 0?
ax2 + c = 0 Subtract c from both sides: ax2 = -c divide both sides by a: x2 = -c/a and so x = ± sqrt(-c/a) This has real solutions only if -c/a ≥ 0, that is, if c/a ≤ 0. Depending on the level you are at, if c/a ≥ 0 then there are the imaginary solutions i*sqrt(c/a).
Write a quadratic equation in the variable x having the given numbers as solutions Type the equation in standard form ax2 plus bx plus c equals 0 Solution 7 is the on solution?
0x2 + 1x - 7 = 0
What is the value of a b and c in the equation ax2 plus bx plus c?
any number
When is there no real solutions for a quadratic equation?
It's when ax2+bx+c=0 if b2-4ac= is negative
What is the function y equals ax2 plus bx plus c?
It is a quadratic function which represents a parabola.
What cant ax2 plus bx plus c equals 0 have?
A discriminant that is less than zero.
What is the general equation for quadratics?
The general quadratic equation is ax2 + bx + c = 0 The two solutions are: x = [ (negative b) plus or minus the square root of (b2 - 4ac) ] all divided by (2a).
What happens when A changes in the equation ax2 Bx c?
If you mean: ax2+bx+c = 0 which is the general form of a quadratic equation whereas a is > 0 and any increases to the value of a will effect the solutions of the equation.
