Sum of an arithmetic series:
Sum = (1st number + last number) x (the number of numbers) /2
Your first number is 2. Your last number is 2 x 100 = 200. The number of numbers in this series is 100 (says so in the question). So your sum equals:
(2 + 200) x 100 / 2 = 202 x 100 / 2 = 10100.
100
Sum of the first n even numbers starting with 0 (counting 0 as the first number, 2 would be the second number.... etc) is n x (n-1)
98. It's less than 100, and 9 + 8 = 17
101
No, the sum of a prime number and a composite number is not always even.
To calculate the sum of all even numbers starting from 20 until the sum exceeds 1000, you can initialize a variable for the sum and a counter starting at 20. In a loop, add the counter to the sum and increment the counter by 2 (to keep it even) until the sum exceeds 1000. The final sum will be the total of all even numbers added. Here's a simple pseudocode example: sum = 0 number = 20 while sum <= 1000: sum += number number += 2
100
102 + 32 = 100 + 9 =109 (not an even number)
Oh, what a happy little question! Let's take a look at those prime numbers. When we add them up, we find that their sum is actually even. Isn't that just a delightful surprise? Remember, in the world of numbers, there's always a little bit of magic waiting to be discovered.
No. Sum of odd + odd = even Sum of odd + even = odd Sum of even + even = even
Sum of the first n even numbers starting with 0 (counting 0 as the first number, 2 would be the second number.... etc) is n x (n-1)
98. It's less than 100, and 9 + 8 = 17
100
The sum of the first 100 positive even numbers is 10,100.
The sum of two odd numbers or two even numbers is an even number. The sum of an odd number and an even number is an odd number.
The sum of the first 100 even numbers is 10,100
The sum of an odd number and an even number is an odd number.