2 more than the sum of 6 and -14:6 + -14 = X + 2 = Desired answer6 + -14 = -8-8 + 2 = -6Answer:-6
It is: (5+2)+6 = 13
7/12 ≈ 0.583 Probability is number_of_ways_of_success/total_number_of_ways. There are 36 possible ways 2 dice can land when thrown. To be more than 6, the sum can be 7, 8, ..., 12 There is 1 way to achieve 12 (6 & 6); 2 ways to achieve 11 (5 & 6 and 6 & 5); ... 6 ways to achieve 7 (1 & 6, 2 & 5, ..., 6 & 1); A Total of 1 + 2 + ... + 6 = 21 ways of getting a sum greater than 6. Thus the probability of throwing a sum greater than 6 is 21/36 = 7/12.
When 2 dice are rolled, the probability of getting a sum less than 4 or greater than 9 is 2 in 9. There are 36 permutations of two six sided dice, 1-1, 1-2, ..., 1-6, 2-1, ... 2-6, ..., 6-1, 6-2, ... 6-6. Of these permutations, 3 have a sum less than four, 1-1, 1-2, and 2-1, and 5 have a sum greater than nine, 4-6, 5-5, 5-6, 6-4, 6-5, and 6-6. Add these probabilities together and you get (3 + 5) in 36, or 8 in 36, or 2 in 9.
5,6,2,3,9 has a greater sum than 10,4,5,1 and 2 which has a sum of 22.
2 more than the sum of 6 and -14:6 + -14 = X + 2 = Desired answer6 + -14 = -8-8 + 2 = -6Answer:-6
It is: (5+2)+6 = 13
6
All you do is add them so it it would be 6
Five times the sum of 6 and a number is 2 more than the numberWrite the equation5(6 + x) - 2 = x30 + 5x - 2 = x5x + 28 = x4x = -28x = -7Check: 5 (6 + (-7)) - 2 = -75(-1) - 2 = -7
7/12 ≈ 0.583 Probability is number_of_ways_of_success/total_number_of_ways. There are 36 possible ways 2 dice can land when thrown. To be more than 6, the sum can be 7, 8, ..., 12 There is 1 way to achieve 12 (6 & 6); 2 ways to achieve 11 (5 & 6 and 6 & 5); ... 6 ways to achieve 7 (1 & 6, 2 & 5, ..., 6 & 1); A Total of 1 + 2 + ... + 6 = 21 ways of getting a sum greater than 6. Thus the probability of throwing a sum greater than 6 is 21/36 = 7/12.
6
The sum of 6 is five times more likely, because there are five ways to roll a 6 but only one way to make a 2.
When 2 dice are rolled, the probability of getting a sum less than 4 or greater than 9 is 2 in 9. There are 36 permutations of two six sided dice, 1-1, 1-2, ..., 1-6, 2-1, ... 2-6, ..., 6-1, 6-2, ... 6-6. Of these permutations, 3 have a sum less than four, 1-1, 1-2, and 2-1, and 5 have a sum greater than nine, 4-6, 5-5, 5-6, 6-4, 6-5, and 6-6. Add these probabilities together and you get (3 + 5) in 36, or 8 in 36, or 2 in 9.
The sum of three times a number and its square is 10 more than 6 times a number?
Not sure about a standard form. It is 2*[N + (6 + 7)] = 2*[N + 13] = 2*N + 26
5,6,2,3,9 has a greater sum than 10,4,5,1 and 2 which has a sum of 22.