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The algebraic expression for the sum of 6 times a number and 5 can be written as ( 6x + 5 ), where ( x ) represents the unknown number. This expression indicates that you first multiply the number by 6 and then add 5 to that product.
6+n = 2n+5
x+5 divided by 2 =6
To find "six less than the square of the sum of 5 and a number," we first express the number as ( x ). The sum of 5 and ( x ) is ( 5 + x ). Squaring this sum gives us ( (5 + x)^2 ). Finally, subtracting 6 results in the expression ( (5 + x)^2 - 6 ).
6(3x + 5) = 18x + 30
5x + 6
0.8333
19
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.
The algebraic expression for the sum of 6 times a number and 5 can be written as ( 6x + 5 ), where ( x ) represents the unknown number. This expression indicates that you first multiply the number by 6 and then add 5 to that product.
6+n = 2n+5
x+5 divided by 2 =6
6(3n+5)
To find "six less than the square of the sum of 5 and a number," we first express the number as ( x ). The sum of 5 and ( x ) is ( 5 + x ). Squaring this sum gives us ( (5 + x)^2 ). Finally, subtracting 6 results in the expression ( (5 + x)^2 - 6 ).
6(3x + 5) = 18x + 30
5 x (6 + n)
The question is ambiguous and the possible answers are n + 5*6 = n + 30 or (n + 5)*6