Set up equation; x = first page number & x+1 = second page number. So, x + x + 1 = 369 or x = 184. X+1 = 185 which is the larger page number.
pages 42 and 43 [you take 85 down one, then halve it, and as it's a book obviously one page will have a higher number that the other.]
52 and 53
The solution is: Let X = left page and X+1 = right page. X + (X+1) = 89. Solve for X; X = 44 which is left page and right page is X+1 = 45.
There is no number of pages in this newspaper section that will sum to 258. The closest is 22 pages, which sums to 253.
This problem can be solved by applying the counting principle to digits in consecutive page numbers. To begin, we need to separate numbers into their numbers of digits in order to multiply the page numbers to find the number of digits needed to express them. Assuming that your book begins on page 1, there are 9 page numbers having one digit only (counting principle: 9 - 1 + 1 = 9). Since each of these pages is numbered with one digit, the number of digits used is 9 so far. Continue with the pages each numbered with two digits. These are pages 10-99, comprising 90 pages (99 - 10 + 1 = 90). Every page number multiplied by 2 digits each is 180. With the 9 digits coming from single-digit pages, the number of digits used so far is now 189. We can continue in the same manner for pages expressed with three digits, 100-999, but having 435 (624 total - 189 so far = 435) digits left, we probably won't be able to get through all the three-digit numbers. Also, a book is likely to have under a thousand pages. To find out how many pages are left, we divide the number of digits left by the number of digits needed for each page: 435/3 = 145 pages left. Since 145 pages only account for the pages numbered with three digits each, we need to add pages numbered with one and two digits each in order to find the total number of pages. Before 145 pages began to be accounted for, we had accounted for the digits of 99 pages (each numbered using one or two digits each), so the total number of pages is 99 + 145 = 244.
122 and 123How?|vif the page is double sided then it has two numbers that are added... divide 245 by 2 and you get 122.5 so one page is pg. 122 and the other is pg. 123
40 & 41
They are 44 and 45.
The book is opened to pages 26, on the left, and 27, on the right. The product of 26 times 27 is 702.
Let the two facing pages be represented by x and (x+1). Since the product of the page numbers is 1056, we have the equation x(x+1) = 1056. This simplifies to x^2 + x - 1056 = 0. By solving this quadratic equation, we find the page numbers to be 32 and 33.
Facing the Future has 160 pages.
There are 331 such numbers.
Facing Mount Kenya has 339 pages.
pages 42 and 43 [you take 85 down one, then halve it, and as it's a book obviously one page will have a higher number that the other.]
First 9 pages = 9 digit. That leaves 142 digits. @ 2 digit per page, that is 142/2 = 71 pages with 2-digit numbers. So, 9 pages with 1-digit numbers + 71 pages with 2-digit numbers = 80 pages.
52 and 53
Books have numbers on the pages so that you can return to that spot if necessary. The number is usually on the bottom of the page. Sometimes a book will have an index that gives page numbers by the subject they contain.