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tn=15-3n

t1=15-3x1=12

t2=15-3x2=9

d=t2-t1/d=9-12=-3

tn=t1+(n-1)xd

tn=12+(12-1)x-3

12+11x-3=12+(-33)=-21=tn

Sn=n/2x(tn+t1)

=S12=12/2 x(-21 +12)

=6 x -9

=-54

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Q: The sum of the first 12 terms of the arithmetic sequence tn=15-3n is?
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