Q: What is the sum of the first ten terms of the arithmetic sequence 4 4.2 4.4...?

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a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....

The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.

sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10

An arithmetic sequence is a list of numbers which follow a rule. A series is the sum of a sequence of numbers.

An arithmetic series is the sum of the terms in an arithmetic progression.

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a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....

The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.

sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10

An arithmetic sequence is a list of numbers which follow a rule. A series is the sum of a sequence of numbers.

An arithmetic series is the sum of the terms in an arithmetic progression.

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The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.

For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.

-5 19 43 67 ...This is an arithmetic sequence because each term differs from the preceding term by a common difference, 24.In order to find the sum of the first 25 terms of the series constructed from the given arithmetic sequence, we need to use the formulaSn = [2t1 + (n - 1)d] (substitute -5 for t1, 25 for n, and 24 for d)S25 = [2(-5) + (25 - 1)24]S25 = -10 + 242S25 = 566Thus, the sum of the first 25 terms of an arithmetic series is 566.

Sum of 1st 2 terms, A2 = 2 + 4 = 6 Sum of 1st 3 terms, A3 = 2 + 4 + 6 = 12 Sum of 1st 4 terms A4 = 2 + 4 + 6 + 12 = 20 you can create a formula for the sum of the 1st n terms of this sequence Sum of 1st n terms of this sequence = n2 + n so the sum of the first 48 terms of the sequence is 482 + 48 = 2352

an arithmetic sequeunce does not have the sum to infinty, and a geometric sequence has.