Q: The sum of three consecutive odd intrgers is 228 what are the inetgers?

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They are: 75+76+77 = 228

Let x equal the lowest number of the three.Therefore:x + x + 1 + x + 2 = 2283x + 3 = 2283x = 228 - 33x = 225x = 75Thus the 3 numbers are 75, 76 & 77.

Let the first one be x, the second be x + 1, and the third one is x + 2. So we have,x + x+1 + x +2 = 2283x + 3 = 228 subtract 3 to both sides3x = 225 divide by 3 to both sidesx = 75x + 1 = 75 + 1 = 76x + 2 = 75 + 2 = 77Thus, the three consecutive integers are 75, 76, and 77.

75 percent off of 228 = 5775% off of 228= 75% discount applied to 228= 228 - (75% * 228)= 228 - (0.75 * 228)= 228 - 171= 57

The Roman numeral for 228 is CCXXVIII. It is represented by the combining of the symbols for 100 (C) and 10 (X), repeated twice, followed by the symbol for 5 (V) and 1 (I), repeated three times.

Related questions

They are: 75+76+77 = 228

The numbers are 226, 227 and 228.

The three numbers added together will equal 228. The average of the three numbers will be 228 / 3 = 76. If you take one even integer from either side of 76, you get 74 and 78.Therefore, the three consecutive even integers which equal 228 are 74, 76 and 78.

The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.

Let x equal the lowest number of the three.Therefore:x + x + 1 + x + 2 = 2283x + 3 = 2283x = 228 - 33x = 225x = 75Thus the 3 numbers are 75, 76 & 77.

The middle number must be the average, so 681/3 = 227 and the other two numbers are 226 and 228.

Let the first one be x, the second be x + 1, and the third one is x + 2. So we have,x + x+1 + x +2 = 2283x + 3 = 228 subtract 3 to both sides3x = 225 divide by 3 to both sidesx = 75x + 1 = 75 + 1 = 76x + 2 = 75 + 2 = 77Thus, the three consecutive integers are 75, 76, and 77.

The sum of any two consecutive integers must be an odd number. So this question is incorrect.

Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228

This would be impossible as, seeing as one of the integers would be odd, the result would be an odd number.

228, 456, 684

75 percent off of 228 = 5775% off of 228= 75% discount applied to 228= 228 - (75% * 228)= 228 - (0.75 * 228)= 228 - 171= 57