Let n be the smaller number of the two.
n + (n+2) = 38
Solving, we have n = 18.
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No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
There are no two consecutive even numbers whose sum is 100. It is easily proved.
The sum of the numbers is 26. The numbers are 12 and 14.
There is no solution. You could do it if the numbers were odd: 25 and 27 are consecutive odd numbers that equal 52.
No, it is impossible.