K is known as the rate coefficient, or the rate constant. The value of k is particular, and varies from reaction to reaction. It is dependent on different factors such as temperature, pressure, concentration, solvent, presence of a catalyst, etc., and therefore a change in any of these gives you a new value for k. To determine the value of k, you must use the experimental data to determine if you have a zeroth order, first order, or second order reaction. As indicated by the equation below, you must also have the actual rate.
Rate= k[A]m[B]n[C]p
Your overall reaction order is given by the sum of the orders of reactant.
If you have a zeroth order reaction overall, then k will be equal to the rate. So if the reactants are consumed at a rate of 1.00 mol/liter/sec, then your k has a value of 1.00 mol/liter/sec. This means that no matter how much of the species you add, a lot or just enough, you will not change the rate.
If you have a first order reaction where the concentration of A, [A] (in mols/liter), is consumed at a rate of .004 mol/liter/sec, then k = [A]/.004 mol/liter/sec, as given by the above equation: You divide the rate by the concentrations of the reactants. The units for a first order reaction are sec-1 or 1/sec, because you are dividing moles per liter by moles per liter per second. So the concentration of this does matter. The concentration of the reactant is proportional to the rate of reaction.
If you have a second order reaction, then the addition of a reactant will increase the rate of reaction by a square of the concentration of the reactant. This is because you are now dividing the rate of reaction by, for example, [HNO3]2. Remember the the previous variables m, n, or p are the experimentally determined order of reactant. So a second order reaction results in squaring the concentration. Hope that helps!
how does the rate law show how concentration changes after the rate of reaction
The rate constant, often denoted as ( k ), is a proportionality factor in the rate law of a chemical reaction. Its formula depends on the order of the reaction. For a first-order reaction, ( k ) has units of ( s^{-1} ), while for a second-order reaction, it has units of ( M^{-1}s^{-1} ). The general expression for the rate law can be represented as ( \text{Rate} = k[A]^n ), where ( [A] ) is the concentration of the reactant and ( n ) is the reaction order.
In the context of chemistry, "k Rate kAmBn" refers to the rate constant (k) of a reaction involving reactants A and B, where "m" and "n" represent the stoichiometric coefficients of these reactants in the rate law. The rate of the reaction can be expressed as proportional to the concentrations of A and B raised to their respective powers, leading to the equation: rate = k [A]^m [B]^n. This relationship helps in understanding how changes in concentration affect the speed of the reaction.
To calculate the rate of a reaction, you typically use the rate law equation, which can be expressed as ( \text{Rate} = k[A]^m[B]^n ), where ( k ) is the rate constant, ( [A] ) and ( [B] ) are the concentrations of the reactants, and ( m ) and ( n ) are their respective orders. Assuming a simple first-order reaction with respect to both A and B (i.e., ( m = n = 1 )), the rate would be calculated as ( \text{Rate} = 0.1 \times (1)^1 \times (2)^1 = 0.2 , \text{M/s} ). Thus, the reaction rate is 0.2 M/s.
Rate of flow varies as R^4 where R is the radius or Rate of flow = (k) x (R^4)
how does the rate law show how concentration changes after the rate of reaction
The rate of a reaction can be determined using the rate law expression, which involves the rate constant (k) and the concentrations of reactants (A and B). Without knowing the specific form of the rate law, we cannot calculate the rate based solely on the values of the concentrations A and B. Additional information about the rate law or the order of the reaction with respect to A and B would be needed.
The rate law for this reaction is rate = k[A][B], where the rate constant k is doubled along with the concentrations of A and B.
A rate constant
The rate law for a zero-order reaction is rate k, where k is the rate constant. In a zero-order reaction, the rate of the reaction is independent of the concentration of the reactants.
If the concentration of NO is halved in a reaction with the rate law rate = k(NO)²(H₂), the rate of the reaction would decrease. Specifically, since the rate is proportional to the square of the concentration of NO, reducing its concentration by half would result in the rate being reduced to one-fourth of its original value, assuming the concentration of H₂ remains constant. Therefore, the new rate would be k(0.5NO)²(H₂) = k(0.25NO²)(H₂) = (1/4) × original rate.
Rate = k[A]m[B]n
The rate law for the reaction A + 2B -> C + D is: rate = k[A][B]^2, where k is the rate constant and [A] and [B] are the concentrations of reactants A and B, respectively.
how does the rate law show how concentration changes after the rate of reaction
The general form of a rate law is rate = k[A]^m[B]^n, where rate is the reaction rate, k is the rate constant, [A] and [B] are the concentrations of reactants A and B, and m and n are the respective reaction orders for A and B.
The rate law expression for a first-order reaction is: Rate kA, where Rate is the reaction rate, k is the rate constant, and A is the concentration of the reactant.
The rate constant can be determined from the rate law by rearranging the rate equation to isolate the constant. For a reaction with a rate law of the form ( \text{Rate} = k[A]^m[B]^n ), where ( k ) is the rate constant, ( [A] ) and ( [B] ) are the concentrations of the reactants, and ( m ) and ( n ) are their respective orders, one can measure the reaction rate at known concentrations. By substituting these values into the rate law and solving for ( k ), the rate constant can be calculated. This process often involves experimental data collected under controlled conditions.