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No, 0.01 is not written as 0.01% in percent rate. 0.01 in percent rate is 1%.
K is known as the rate coefficient, or the rate constant. The value of k is particular, and varies from reaction to reaction. It is dependent on different factors such as temperature, pressure, concentration, solvent, presence of a catalyst, etc., and therefore a change in any of these gives you a new value for k. To determine the value of k, you must use the experimental data to determine if you have a zeroth order, first order, or second order reaction. As indicated by the equation below, you must also have the actual rate.Rate= k[A]m[B]n[C]pYour overall reaction order is given by the sum of the orders of reactant.If you have a zeroth order reaction overall, then k will be equal to the rate. So if the reactants are consumed at a rate of 1.00 mol/liter/sec, then your k has a value of 1.00 mol/liter/sec. This means that no matter how much of the species you add, a lot or just enough, you will not change the rate.If you have a first order reaction where the concentration of A, [A] (in mols/liter), is consumed at a rate of .004 mol/liter/sec, then k = [A]/.004 mol/liter/sec, as given by the above equation: You divide the rate by the concentrations of the reactants. The units for a first order reaction are sec-1 or 1/sec, because you are dividing moles per liter by moles per liter per second. So the concentration of this does matter. The concentration of the reactant is proportional to the rate of reaction.If you have a second order reaction, then the addition of a reactant will increase the rate of reaction by a square of the concentration of the reactant. This is because you are now dividing the rate of reaction by, for example, [HNO3]2. Remember the the previous variables m, n, or p are the experimentally determined order of reactant. So a second order reaction results in squaring the concentration. Hope that helps!
4,5 (mol/L)/s
1
With only one year the value is 11600
In a zero order overall process, the rate and rate constant will be the same. (Reaction order is an exponent, and if that exponent is "0" then the value is "1" and will cancel out.)
If the concentration of H2 were halved, the rate of the reaction would also be halved, assuming H2 is part of the rate-determining step. The rate law rate = k[NO2][H2] shows that the rate is directly proportional to the concentration of H2.
0.4 (mol/L)/s
No, 0.01 is not written as 0.01% in percent rate. 0.01 in percent rate is 1%.
The overall reaction order for the rate law rate = k[A]^2[B][C] is 4, which is calculated by summing the individual reaction orders for each reactant ([A]^2 has an order of 2, [B] has an order of 1, [C] has an order of 1).
The theoretical rate constant value for the hydrolysis of ethyl acetate is approximately 1.0 x 10^-6 s^-1 at room temperature. This reaction is catalyzed by acid or base, with acid-catalyzed hydrolysis generally being faster. The actual rate constant value may vary depending on the specific conditions of the reaction.
Chain Reaction - 1980 1980-04-01 was released on: USA: 1 April 1980
Chain Reaction - 1980 1980-05-01 was released on: USA: 1 May 1980
If the concentration of NO is halved, the rate of the reaction will also be halved. This is because the rate of the reaction is directly proportional to the concentration of NO raised to the power of its coefficient in the rate law (in this case 1). So, halving the concentration of NO will result in a proportional decrease in the rate of the reaction.
1. The rate of forward reaction = to the rate of backward reaction. 2. Concentration of the substance are constant.
A 1.5 order of reaction refers to a reaction where the rate of the reaction is directly proportional to the concentration of one reactant raised to the power of 1.5. This type of reaction does not follow typical integer orders such as first, second, or zero order reactions. The reaction rate is proportional to the square root of the concentration of the reactant.
The reaction is first order with respect to the reactant. The rate constant k can be determined by using the rate equation in the form rate = k [A]. By plugging in the values for rate and concentration at both conditions, you can solve for k. The rate constant k in this case would be 1.59 × 10^3 M^-1 s^-1.