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Let the polynomial be y = ax^2 + bx + c

The derivative or slope at the minimum is zero: 2ax + b = 0

We have 55 = a (4^2) + b (4) + c

25 = a (3^2) + b (3) + c

and 2a(3) + b = 0 or b = -6a

55 = 16a - 24a + c = -6a + c

25 = 9a -18a +c = - 9a + c

30 = 3a

a = 10

b = -60

c = 55 + 6a = 115

The parabola is y = 10x^2 - 60x + 115

Check using, for instance

http://www.wolframalpha.com/input/?i=evaluate+y+%3D+10x^2+-+60x+%2B+115+at+x%3D3

and

http://www.wolframalpha.com/input/?i=minimize++10x^2+-+60x+%2B+115

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What equation describes a parabola that opens up or down and whose vertex is at the point (h v)?

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