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Probability of first green: 5/7

Probability of second green: 5/7

Probability of a red: 2/7

Probability of all 3 consecutive successes: (5/7) x (5/7) x (2/7) = 50/343 = 14.58% (rounded)

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Q: There are 2 red and 5 green balls in a bag If you randomly choose balls one at a time with replacement what is the probability of choosing 2 green balls and then 1 red ball?
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