The colors don't matter. And I'm having to assume from your description that you mean that the smaller cubes have sides of length 2 cm long. Thus, there are 64 cubes. 8 have three sides painted. 24 have two sides painted. 24 have one side painted. 8 have no sides painted.
cube has 6 sides so 3 cubes have 3*6 = 18.
No. A cube with sides which are 1 centimetre long or that of 1 inch are both unit cubes, as is a cube with sides of 1 decimetre (volume = 1 litre).
Only the 8 corner cubelets of the original large cube will have three painted faces.
Each side will be 5 x 5 and the 3 x 3 in the centres will have 1 painted face so total will be 6 x 3 x 3 ie 54.
How many smaller cubes are not painted at all if a cube is painted green on all sides & cut into 64 cubes of equal size?
0 sides are not painted! So all the cubes have three faces painted!
The entire outer layer is painted so an 8x8x8 block inside isn't painted. Zero. All cubes are painted on at least one side and the 10x10x10 cube is painted on all sides. It's a 10x10x10 cube meaning there are 1000 cubelets. Ones on the inside too. So 8x8x8 = 512.
A cube, by definition, has six sides. There cannot be a 40-sided cube.
I am assuming that your question states that the top and sides are painted red but the bottom isn't. If so, the answer is:- There are no cubes with 4 faces painted, the most that can be painted is 3 for the ones on the corners. There are 4 corners at the top of the cube that will have their top and 2 sides painted. Therefore there are 4 cubes with 3 painted. The cubes at the corners on the second and third row down will have 2 faces painted, as will the middle cubes on the top row so there are 12 of them in this puzzle. The cube in the middle of each painted face will have just one face painted so this is 5 (assuming the bottom isn't painted). The cubes in the middle of the bottom row will also have one face painted. This brings the total to 9 That is the total of cubes that have paint on them... 4+12+9 = 25 There are 27 cubes in your puzzle so only 2 have no painted faces. The cube right in the middle and the cube in the middle of the bottom layer.
it is very simple.. number of cubes painted in all three sides is always 8. number of cubes painted in 0 sides is (n-2)^3 number of cubes painted in 1 side is 6(n-2)^2 number of cubes painted in 2 sides is 12(n-2) here n is n x n x n sides...... (eg.. if any 10 x 10 x10 sides is cut into 1 cube then n=10, if any 10 x 10 x10 sides is cut into 2 cubes then n=10/2 = 5)
Cube root of 64 is 4 therefore cube is 4 x 4 x 4. Each side of the cube has 16 visible small cube faces, 4 of which are corners (3 green sides) and 8 more are edges (2 green sides), so there are only four small cubes with one green face on each of the six sides of the large cube. Your answer is therefore 24.
All the little cubes except the one at the middle will have 1, 2 or 3 faces with paint on them, ie 26 of them will have some paint on them: 0 faces painted - 1 cube 1 face painted - 6 cubes (the centre ones of each side) 2 faces painted - 12 cubes (the ones in the centre of where two sides meet) 3 faces painted - 8 cubes (the ones in the corners).
The colors don't matter. And I'm having to assume from your description that you mean that the smaller cubes have sides of length 2 cm long. Thus, there are 64 cubes. 8 have three sides painted. 24 have two sides painted. 24 have one side painted. 8 have no sides painted.
The colors don't matter. And I'm having to assume from your description that you mean that the smaller cubes have sides of length 2 cm long. Thus, there are 64 cubes. 8 have three sides painted. 24 have two sides painted. 24 have one side painted. 8 have no sides painted.
8
12