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Algebraically. X = integers.

X + (X + 2) + (X + 4) = 42

3X + 6 = 42

3X = 36

X = 12

X + 2 = 14

X + 4 = 16

12 + 14 + 16 = 42

-----------------------------so,

(12, 14, 16)

----------------------solution set

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Q: Three consecutive even integers that have a sum of 42?
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