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Let the speed of the train be ( x ) km/h. Then the speed of the plane is ( 4x - 20 ) km/h. Since time is equal for both, we can set up the equation:

[ \frac{200}{x} = \frac{700}{4x - 20} ]

Cross-multiplying and simplifying gives us ( 200(4x - 20) = 700x ), leading to ( 800x - 4000 = 700x ). Solving this results in ( 100x = 4000 ), so ( x = 40 ) km/h for the train and ( 4(40) - 20 = 140 ) km/h for the plane. Thus, the train's speed is 40 km/h and the plane's speed is 140 km/h.

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4mo ago

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