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If p is an integer between 1000 and 1030 and if the sum of the digits of p is odd then p must be odd?
If ( p ) is an integer between 1000 and 1030, it can be expressed as ( p = 1000 + n ), where ( n ) ranges from 0 to 30. The sum of the digits of ( p ) is given by ( 1 + \text{(sum of the digits of } n) ). Since 1 is odd, for the total sum of the digits to be odd, the sum of the digits of ( n ) must be even. As a result, if ( p ) is odd, ( n ) must be odd (e.g., 1, 3, 5, etc.), confirming that ( p ) is indeed odd. Thus, the statement is true: if the sum of the digits of ( p ) is odd, then ( p ) must be odd.
How do you translate The sum of 6 and a number is equal to twice the number increased by 5?
6+n = 2n+5
How do you write a equation when the sum of a positive number and several negative numbers will be positive?
if p represents your positive number, and n represents all of your negative numbers, then: |∑n| < p
What is the sum expression for the sum of n and 5?
The sum of n and 5 is n+ 5
C program to find sum of 'n' number using function?
void main () { int no1, sum, n; clrscr() sum = 0; n = 1; printf("\n enter the number to which sum is to be generated"); scanf("%d",&no1); while(n<=no1) { sum=sum+n; n=n+1 } printf("\n the sum of %d = %d, no1, sum"); getch (); }
How do you translate the sum of 18 and a number?
18 + n
Write a C program for sum of n numbers using pointers?
void main() { int n=0,i,*p; clrscr(); printf("enter the value of n"); scanf("%d",&n); p=&n; for(i=0;i<=n;i++) { *p=*p+i; } printf("value of the sum is %d",*p); getch(); }
If p is an integer between 1000 and 1030 and if the sum of the digits of p is odd then p must be odd?
If ( p ) is an integer between 1000 and 1030, it can be expressed as ( p = 1000 + n ), where ( n ) ranges from 0 to 30. The sum of the digits of ( p ) is given by ( 1 + \text{(sum of the digits of } n) ). Since 1 is odd, for the total sum of the digits to be odd, the sum of the digits of ( n ) must be even. As a result, if ( p ) is odd, ( n ) must be odd (e.g., 1, 3, 5, etc.), confirming that ( p ) is indeed odd. Thus, the statement is true: if the sum of the digits of ( p ) is odd, then ( p ) must be odd.
Can some one translate Twice the sum of a number and 3?
2(n+3)
How do you translate The sum of 6 and a number is equal to twice the number increased by 5?
6+n = 2n+5
Translate the following phrase into an algebraic expression -the quotient of the sum of two numbers and twenty?
The quotient of two and the sum of a number and twenty
The emmiter current of an n-p-n transistor is equal to?
The sum of (base current) plus (collector current).
Translate the verbal phrase into an expression 3 less than the square of a number p?
3(n-9)
How do you write a equation when the sum of a positive number and several negative numbers will be positive?
if p represents your positive number, and n represents all of your negative numbers, then: |∑n| < p
How would you write out a conditions when the sum of a positive number and several negative numbers will be positive?
if p represents your positive number, and n represents all of your negative numbers, then: |∑n| < p
A natural number N has four factors The sum of factors excluding the number is 31 How many values can N have?
The natural number N with four factors can be expressed as N = p^3, where p is a prime number. Given that the sum of factors excluding N is 31, the factors are 1, p, p^2, and the sum of these factors is 1 + p + p^2 = 31. Solving the equation p^2 + p - 30 = 0, we find two possible values for p: p = 5 or p = -6. However, since p must be a prime number, the only valid value is p = 5. Therefore, N can have only one value, which is 5^3 = 125.
What is the sum expression for the sum of n and 5?
The sum of n and 5 is n+ 5
