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Area of a trangle = 1/2(base*height)

height or altitude = 2*(60/20) = 6 m

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What is the area of a triangle whose base is 12cm and an altitude of 10cm?

The area of triangle is : 60.0


What is the altitude of an eqilateral triangle having base equal to 3 foot?

An equilateral triangle is baisicaly 2 30-60-90 tiangles put together. The height of the longer lg of a 30-60-90 triangle is always root 3 times the length of the shorter leg. Because the length of the shorter legs of the 2 30-60-90 triangles in the equilateral triangle is half the base, the altitude is 31/2/2*b where b is the base.


The perimeter of an equilateral triangle is 32centimeters find the length of an altitude of the triagle to the nearest tenth of a centimeter?

Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm. If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have, sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides) (32/3 cm)sin 60⁰ = altitude 9.2 cm = altitude


What is the altitude of a triangle if it has side length of 60 inche?

It can be any length at all. The length of one side imposes no limits at all on the altitude.


How do you construct equilateral triangle if only altitude is given?

Use trigonometry knowing that the angle will be 60 degrees


The perimeter of an equilateral triangle is 45 centimetersFind the length of an altitude?

Each side of the triangle is 45cm/3=15cm. The altitude divides the base into two equal segments of 7.5cm. This results in a right triangle with hypotenuse 15 cm and base 7.5cm. Pythagorus tells us a2+b2=c2 where a=altitude, b=base, c=hypotenuse. a2=c2-b2=152-7.52=225-56.25=168.75, a=12.99cm. Alternatively, the 3 angles of an equilateral triangle are all 60 degrees. The altitude divides one of these angles into two 30 degree angles. The cosine of 30 degrees is the opposite divided by the adjacent side. The adjacent side is the altitude. Thus a/c=cosine of 30 degrees, a=c X cos30 degrees = 15X0.866=12.99cm


What is the base measurement of triangle with an area of 30m and a height of 10m?

The area of a triangle is one-half the product of the base and the height. Therefore, the base of this triangle must be 60/10 = 6 meters.


The length of one side of an equilateral triangle is 11 Find the length of the altitude?

each angle is 60 degrees. If you know trigonometry sin 60 = Altitude/length of side (from Pythagoras) A = 9.526 inch Or, from Pythagoras theorem 5.5 squared + Altitude squared = 11 squared Altitude = 9.526


Find the area of a triangle where the base is 10cm and height is 12cm?

60 sq cm


How long are each sides of an equilateral triangle if the perimeter is 60?

20. There are 3 sides to any triangle. For an equilateral triangle all 3 sides are the same length. Therefore for this triangle we can say that, where x equals the length of a side: 3x = 60 x = 60/3 x = 20


What is the area of 60 and 40 yd in a triangle?

Area of a triangle in square units = 0.5*base*height


How do you find the area of an equalateral triangle?

Do you mean an equilateral triangle? Then if so then the formula for the area of any triangle: 0.5*a*b*sinC whereas a and b are the embraced sides of angle C And in the case of an equilateral triangle it is: 0.5*any side squared*sin(60 degrees) Alternatively use Pythagoras' theorem to find the altitude of the triangle then use: 0.5*base*height = area