Since the chords are equidistant from the circle centre, they are also the same length.
Hence AB = CD
Substituting
4x - 8 = 28 - 2x
Add '2x' to both sides
Hence
6x - 8 = 28
Add '8' to both sides
6x = 36
Divide both sides by '6'
Hence x = 6
7
Chords equidistant from the center of a circle have equal length, so3x + 7 = 27xSubtract 3x from each side:7 = 24xDivide each side by 24:x = 7/24
If two chords intersect within a circle, the product of the two segments of one chord equals the product of the two segments of the other chord. In short, if two chords intersect in a circle, their length is equal.
The locus of points equidistant from lines y = 0 and x = 3 is the line y = -x + 3.
The diameter of the circle is the length running through the center. From one side to the other. Note: Two times the radius, equals the diameter.
7
Chords equidistant from the center of a circle have equal length, so3x + 7 = 27xSubtract 3x from each side:7 = 24xDivide each side by 24:x = 7/24
Any circle centered at the origin fits that description.
If two chords intersect within a circle, the product of the two segments of one chord equals the product of the two segments of the other chord. In short, if two chords intersect in a circle, their length is equal.
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
The locus of points equidistant from lines y = 0 and x = 3 is the line y = -x + 3.
56
Draw a circle with its center at the origin and a radius of 3.
(x-9)2 + y2 = 484The center is atx = 9y = 0The radius of the circle is 22 .
The diameter of the circle is the length running through the center. From one side to the other. Note: Two times the radius, equals the diameter.
That's the equation of a circle with its center at the origin and a radius of 8.
x2 + y2 = 49