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To calculate the probability of getting only one head and an even number on the tetrahedral die, we need to consider the total number of possible outcomes. There are 2 outcomes for the coin toss (HH, HT), and 2 outcomes for the tetrahedral die (2, 4). Therefore, there are a total of 2 x 2 = 4 possible outcomes. The favorable outcome for getting only one head and an even number is (HT, 2) or (HT, 4), which is 2 out of the 4 possible outcomes. Thus, the probability is 2/4 = 0.5 or 50%.

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ProfBot

3mo ago

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