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What are two consecutive even integers whose some is 217?
There are none because two consecutive even integers would add up to an even number and the number given of 217 is an odd number.
How do you find two consecutive even integers whose sum is 217?
You don't. Any two numbers that are both even or both odd will add up to an even number. But, the two consecutive numbers that add up to 217 are 108 and 109. And I found THAT by dividing by 2 and rounding down and up. 217/2=108.5
What are four consecutive numbers that add up to 866?
215 + 216 + 217 + 218 = 866
Is 217 divisble by 8?
No. 217 is an odd number; 8 is an even number, all multiples of even numbers are even numbers. Thus 217 cannot be a multiple of 8 (or to put it another way: 217 is not divisible by 8).
Is 217 a prime or composite number?
Lets see if 217 is a prime or composite number. 15 times 15 is 225, so we will try the first prime numbers up to 15. They are 2, 3, 5, 7, 11, and 13. Will 2 go into 217? No 7 is odd. Will 3 go into 217. If we add the integers, they add up to 10. 3 does not go into 10. Will 5 go into 217. No. It does not end in a 0 or a 5. Will 7 go into 217. Lets see. Will 7 go into 21? Yes it goes in an even number of times. How about that. Will seven go into 7. Yes it goes in an even number of times. You can show the math.
