There are none because two consecutive even integers would add up to an even number and the number given of 217 is an odd number.
The number 217 is odd. Two even number add up to an even number so there are not two consecutive even number that total 217. Let 2m be any even number, 2k be another one There sum is 2(m+k) which is even.
The numbers are 62 and 64 are two consecutive integers that equal 126.
You don't. Any two numbers that are both even or both odd will add up to an even number. But, the two consecutive numbers that add up to 217 are 108 and 109. And I found THAT by dividing by 2 and rounding down and up. 217/2=108.5
28 + 30 = 58
There are none. The only two consecutive integers totaling 217 are 108 and 109.
There are none because two consecutive even integers would add up to an even number and the number given of 217 is an odd number.
This question can't have an answer that satisfies the given conditions.The sum of any two even integers is always an even number, but 217 is an odd number.If the sum were 218 instead of 217, then 108 and 110 would do the job.
The number 217 is odd. Two even number add up to an even number so there are not two consecutive even number that total 217. Let 2m be any even number, 2k be another one There sum is 2(m+k) which is even.
The numbers are 62 and 64 are two consecutive integers that equal 126.
There are no "two consecutive integers" that can do that.But there are two consecutive even integers that can: 8 and 10 .
There are two consecutive even integers that equal -298: -150 and -148.
You don't. Any two numbers that are both even or both odd will add up to an even number. But, the two consecutive numbers that add up to 217 are 108 and 109. And I found THAT by dividing by 2 and rounding down and up. 217/2=108.5
The sum of two consecutive odd integers is an even number. There is no possible answer to this question.
28 + 30 = 58
There are no two consecutive even numbers whose sum is 100. It is easily proved.
There are two consecutive even integers: 90 and 92.