1.27 cm*1 in
2.54 cm=0.5 in
1.27 cm = 0.5 inches, so the formula would be:
10 feet X
--------- = -------
0.5 inch 1 inch
20 feet = X
So the answer is 20 feet
The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6
multiply the length by the width to find the area
You measure length in many ways: using a ruler or yardstick, using a string or tape measure, using a machine to drive or fly over a distance, or using a satellite. Length is measured in units such as centimeters, meters, kilometers, or inches, yards and miles.
It is the distance between the end points of a line measured using Imperial units.
Convert the following using the step method hint use your worksheets
52.5 feet
Using a graduated ruler, a surveyors wheel or trundle wheel, or by using an optical (Tachymeter) or laser range finder are methods that may be used to find length or distance.
You are calculating the length of a line segment
The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6
Using the distance formula the length of ab is 5 units
It is a measure of length or distance, using the old Imperial units.
Mexico primarily uses the metric system to measure length and distance. Common units include centimeters, meters, and kilometers. In some cases, inches and feet from the imperial system may also be used in informal settings.
multiply the length by the width to find the area
Using the distance formula the length of ab is 5 units
Using the distance formula the length of ab is 5 units
The focal length of a concave mirror can be found by using the mirror formula, which is 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance. By measuring the object and image distances from the mirror, you can calculate the focal length using this formula.
Using a yardstick, I measured the table's length.He cut off a length of string.The length of a hallway is usually more than its width.