Ax5
It depends on the phase and the temperature Solid AlCl3 has each aluminium is 6 coordinate, surrounded by 6 chlorine atoms in an octahedral formation. The best description here is a ionic bonding. Interestingly just below melt temperature the conductivity rises indicating free ions. AlCl3 in the melt is found as dimer Al2Cl6 with four coordinate aluminium. Two chlorines bridging the aluminium atoms. In this aluminium achieves its octet and the bond angles are in line with VSEPR theory. At high temperature the dimers dissociate to monomeric AlCl3 which is trigonal planar, following VSEPR theory.
120o. The polyatomic ion is planar with a trigonal molecular geometry, a nitrogen atom with 3 equidistant O atoms at near 122 pm. All predictable ny VSEPR. The short bond length is attributed to pi bonding, the negative charge is spread across the three O atoms.
The shape around S is trigonal pyramidal. Direction of deviation is less than ideal. The shape around O-H is bent (V-shaped). Direction of deviation less than ideal.
When you do the VSEPR you get 6pairs of electron pairs and two lone pairs which means that when you look at the geometrical shape (by looking at how many pairs of electrons you got and in this cases its 6) the shape is octahedral but the molecular shape is square planar because you only have four atoms bonding and two lone pairs which means that the lone pairs have to be as far from each other as possible so they go on the two ends ( one on top and one on the bottom) which leavs the shape to be a square planar! i hope this helps you good luck. --------- TL;DR: Square Planar.
The VSEPR formulas that predict a trigonal bipyramidal shape are AX₅ and AX₄E. In both cases, there are five electron groups around the central atom, leading to a trigonal bipyramidal geometry with angles of 90° and 120°.
BF3 has a trigonal planar molecular geometry according to the VSEPR theory. It consists of three bonding pairs around the central Boron atom, resulting in a flat, trigonal planar shape.
H3O: Trigonal pyramidal CO3^2-: Trigonal planar SF6: Octahedral
Ax5
The VSEPR (Valence Shell Electron Pair Repulsion) theory predicts the geometric shape of a molecule based on the repulsion between electron pairs surrounding the central atom. In a molecule with four electron pairs around the central atom, the VSEPR formula would predict a tetrahedral shape, where the bond angles are approximately 109.5 degrees.
BH3 has a trigonal planar shape with 120 angles.
The formula ab3 corresponds to a trigonal planar shape in VSEPR theory. This means that the central atom is surrounded by three bonded atoms and has a bond angle of 120 degrees between them.
The VSEPR formula for a polar molecule would involve a central atom bonded to small, highly electronegative atoms like fluorine or oxygen. For example, molecules like BF3 (Trigonal Planar) or H2O (Bent) tend to have greater polarity due to the electronegativity differences between the central atom and surrounding atoms.
BCl3 and PCl3 are non-polar molecules because they have a symmetrical trigonal planar geometry, causing the bond dipoles to cancel each other out. H2O and NH3 are polar molecules due to their bent and trigonal pyramidal geometries, respectively, which result in an uneven distribution of electron density.
The molecular shape of Br2 in VSEPR theory is linear. This is because Br2 consists of two bromine atoms bonded together with a single bond, resulting in a linear geometry with a bond angle of 180 degrees.
In VSEPR theory, electron groups (bonding pairs and lone pairs) around a central atom arrange themselves in a way that minimizes repulsion, resulting in various molecular geometries such as linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. The number of electron groups around the central atom determines the molecular geometry.
trigonal bipyramidal, there are 5 e- by VSEPR method