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The above question contains no symbol between on either side of 36.
Suppose the length and width are L and W Perimeter = 2(L+W) = 200 so L+W = 100 so L= 100-W Area = L*W = 2400 so (100-W)*W = 2400 W2 - 100W + 2400 = 0 W = (100 +/- sqrt(10000 - 4*2400))/2 where the minus sign will give W and the plus sign will give L So W = (100 - sqrt(400))/2 = (100 - 20)/2 = 80/2 = 40 feet So L = 100-40 = 60 feet
To determine the surface area of a period (right rectangular), there is a unique formula. It is lw+l to the square root of w/2 squared + h squared + w square root of (l/2) squared + h squared. L=Length, W=Width, H=Height.
cm squared
Since w^3 is a multiple of w^2, it is automatically the LCM.
(w2)3 = w(2 x 3) = w6
When you multiply W squared by W squared, you are essentially multiplying W raised to the power of 2 by W raised to the power of 2. This results in W raised to the power of 4, as you add the exponents when multiplying like bases. Therefore, W squared times W squared equals W to the power of 4.
If it's a S&W; 100-300 or so
It depends on the value of w. w < 6 then 6w < 36 w = 6 then 6w = 36 and w > 6 then 6w >36
Suppose the length and width are L and W Perimeter = 2(L+W) = 200 so L+W = 100 so L= 100-W Area = L*W = 2400 so (100-W)*W = 2400 W2 - 100W + 2400 = 0 W = (100 +/- sqrt(10000 - 4*2400))/2 where the minus sign will give W and the plus sign will give L So W = (100 - sqrt(400))/2 = (100 - 20)/2 = 80/2 = 40 feet So L = 100-40 = 60 feet
-36 + 2w = -8w + w -36 + 2w = -7w -36 = -7w - 2w -36 = -9w w = -36/-9 = 4
Six less than a number w squared is written algebraically as w2 - 6
(w + 2)(w - 7)
To determine the surface area of a period (right rectangular), there is a unique formula. It is lw+l to the square root of w/2 squared + h squared + w square root of (l/2) squared + h squared. L=Length, W=Width, H=Height.
cm squared
Since w^3 is a multiple of w^2, it is automatically the LCM.
(w2)3 = w(2 x 3) = w6
100 divided by w, or, 100/w. It depends on what w is. If you know w, then just plug it in and divide.