Using Pythagoras' theorem its width is 6 units in length.
A = 48 units2
The area of the rectangle is 72 square feet
The best way to do this would be to use the Pythagorean Theorem, but in reverse. So let's say the diagonal is 10, and the width is 8. You would do (10^2) / (8^2). This equals 36. The square root of 36 is 6. So your answer would be 6 for the length. Hope this answer helps!
I think you mean the width is 6. The answer depends entirely on what the length of the rectangle is. For example, if it is a square, so that the length and width are both 6, the answer is 24. I the length is 10, the perimeter is 32. In general, just add the width (6) to the length and double the sum to get the perimeter.
Diagonal = 10 meters.
Using Pythagoras' theorem its width is 6 units in length.
62 +82 = 102 so 6 and 8
Using Pythagoras' theorem it is about 10.81665383 inches.
length times width
area of a rectangle = length * width. Rearranging, we have width = area / length. Therefore, the width of the rectangle = 31.2 [m2] / 6 [m] = 5.2 [m] ========================
A = 48 units2
The width of the rectangle is 8. 48/6 = 8
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
The area of the rectangle is 72 square feet
The best way to do this would be to use the Pythagorean Theorem, but in reverse. So let's say the diagonal is 10, and the width is 8. You would do (10^2) / (8^2). This equals 36. The square root of 36 is 6. So your answer would be 6 for the length. Hope this answer helps!
Area = Length * Width 24 = 6 * Width so width = 4m