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To find the diagonal of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal (d) is the hypotenuse, and the length (l) and width (w) are the other two sides. So, d^2 = l^2 + w^2. Plugging in the values, we get d^2 = 6^2 + 8^2 = 36 + 64 = 100. Therefore, the diagonal is the square root of 100, which is 10.
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Blake
CoachThe diagonal = the square root of (6 squared + 8 squared)
6 squared+8squared = 100
the square root of 100 = 10
so the length of the diagonal is 10.
The above used Pythagoras' theorem which says the square on the diagonal is equal to the sum of the squares on the other two sides.
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A rectangle has a diagonal of 10 and a length of 8. what is its width?
Using Pythagoras' theorem its width is 6 units in length.
Width of a rectangle is 6 and the diagonal is 10 what is the area?
A = 48 units2
If a rectangle has a length of 12 feet and a width of 6 feet what is the area of the rectangle What is the area of a rectangle with the width of 6 feet and the length of 12 feet?
The area of the rectangle is 72 square feet
How do you find the length of a rectangle if you have the diagonal and width?
The best way to do this would be to use the Pythagorean Theorem, but in reverse. So let's say the diagonal is 10, and the width is 8. You would do (10^2) / (8^2). This equals 36. The square root of 36 is 6. So your answer would be 6 for the length. Hope this answer helps!
What is the perimeter of a rectangle whose with is 6?
I think you mean the width is 6. The answer depends entirely on what the length of the rectangle is. For example, if it is a square, so that the length and width are both 6, the answer is 24. I the length is 10, the perimeter is 32. In general, just add the width (6) to the length and double the sum to get the perimeter.
