(x^2-4) (x^2+6x+8) __________ x _________ which is (x^2+2x-8) (x^2+4x+4) (x+2)(x-2) (x^2+4x+2x+8) ___________ x _____________ which is (x^2+4x-2x-8) (x^2+2x+2x+4) (x+2)(x-2) x(x+4)+2(x+4) ___________ x ____________ which is x(x+4)-2(x+4) x(x+2)+2(x+2) (x+2)(x-2) (x+2)(x+4) ________ x _________ which is 1 as all the terms in the num & den cancel (x-2)(x+4) (x+2)(x+2)
2 x 2 = 4 2 x 2 x 2 = 8
1 x 8, 2 x 4, 4 x 2, 8 x 1.
1 x 8, 2 x 4 8 = 1 x 88 = 2 x 4
128 ounces 8 ounces in a cup and two cups in a pint. 8 x 2 = 16 2 pints in quart 8 x 2 x 2 = 16 x 2 = 32 4 quarts in a gallon 8 x 2 x 2 x 4 = 16 x 2 x 4 = 32 x 4 = 128 128 ounces in a gallon 8 x 2 x 2 x 4 = 128
-2
Well, honey, if you want numbers that multiply to 8, you're looking at 2 and 4. They may not be the most exciting numbers at the party, but they definitely get the job done when it comes to multiplying to 8. So, there you have it, 2 and 4 are the dynamic duo you're looking for when it comes to multiplying to 8.
x-2+4=-8 x+2=-8 x=-10
The remainder is 8. (x2 + 4)/(x - 2) = (x + 2) + 8/(x - 2) or x2 + 4 = (x - 2)(x + 2) + 8
(x^2-4) (x^2+6x+8) __________ x _________ which is (x^2+2x-8) (x^2+4x+4) (x+2)(x-2) (x^2+4x+2x+8) ___________ x _____________ which is (x^2+4x-2x-8) (x^2+2x+2x+4) (x+2)(x-2) x(x+4)+2(x+4) ___________ x ____________ which is x(x+4)-2(x+4) x(x+2)+2(x+2) (x+2)(x-2) (x+2)(x+4) ________ x _________ which is 1 as all the terms in the num & den cancel (x-2)(x+4) (x+2)(x+2)
2 x 2 = 4 2 x 2 x 2 = 8
2 x 2 = 4 2 x 2 x 2 = 8
Half of 4 x 4 x 8 is not 2 x 2 x 2. It's 2 x 4 x 8.
1 x 8, 2 x 4, 4 x 2, 8 x 1.
the proper factors of 8 are 1, 2, and 4. Proper factors are the factors of 8 which are 1, 2, 4, and 8 but not including itself.
2 x 2 x 2 = 8 2 x 2 x 13 = 52 2 x 2 = 4, the GCF
2 x 16 4 x 8 8 x 4 16 x 2