4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
Composite. It is divisible by 3 for any n.
6(n - 4)(n + 1) n = 4, -1
8 (again) The sequence is generated by t(n) = (-n3 + 6n2 + 7n - 12)/6 for n = 1, 2, 3, ...
The equation for the number of 1 cm3 cubes to form a n3 cm3 hollow cube (n>1): 6n2-12n+8 (hint: cubes have 6 faces, 12 edges, and 8 vertices) I'm not sure whether you are asking about a 10 cm3 cube or a 103 cm3 cube. Since you can't divide a 10 cm3 cube into 1 cm3 pieces, I am going to assume you mean a 103 cm3 cube. This cube will yield 1000 1 cm3 cubes. For n=13, 6n2-12n+8 = 866 For n=14, 6n2-12n+8 = 1016 So, with 1000 little cubes, you can form a 13x13x13 cm hollow cube with 134 little cubes left out.
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
2n(3n + 8)
6n2+6n+1
6n2
(3m+2n)(m+3n)
Composite. It is divisible by 3 for any n.
6(n - 4)(n + 1) n = 4, -1
6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.
The chemical equation for nitroglycerin is 4C3H5N3O9 -> 6N2 + 10H2O + 12CO2 + O2.
-8. The numbers can be generated by the following quadratic: t(n) = -6n2 + 23n - 4 for n = 1, 2, 3, ...
was this answered becuase i need to know too
The pattern is Un = 6n2 - 7n + 1 = (6n - 1)*(n - 1) where n = 1, 2, 3, ...