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Let xy x plus 2y and let xy x - z. Solve the following system of equations for x y and z (xy)z 4 x plus (x(y2))(-z) -2 (xy)(-z) 2?
To solve the system of equations given by ( xy = x + 2y ) and ( xy = x - z ), we can start by equating the two expressions for ( xy ). Setting ( x + 2y = x - z ) gives us ( 2y + z = 0 ) or ( z = -2y ). Substituting ( z ) into the other equation leads to a system that can be solved for ( x ) and ( y ). However, without numerical values or additional equations, we cannot find unique solutions for ( x, y, ) and ( z ).
Simplify 2x plus 6 2y plus 3y?
-4(7x-3y-z)-(-6)(9x-z+2)
Simplify 2y plus y plus 3z-z?
3y+2z
How do you factor 18x squared yz plus 12xy squared z plus 6xyz squared?
6xyz(3x + 2y + z)
what- choose the property of equality that justifies the step. prove: if z- 1= 5x+ 1 and x= 2y, then z +10y +2?
addition
Solve the following system of equations x plus 2y -6 equals z 3y-2z equals 7 4 plus 3x equals 2y -5z?
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25
What is the binomial factor of 64y9-8z6?
8(2y^3 - z^2)(4y^6 + 2y^3z^2 + z^4)
Let xy x plus 2y and let xy x - z. Solve the following system of equations for x y and z (xy)z 4 x plus (x(y2))(-z) -2 (xy)(-z) 2?
To solve the system of equations given by ( xy = x + 2y ) and ( xy = x - z ), we can start by equating the two expressions for ( xy ). Setting ( x + 2y = x - z ) gives us ( 2y + z = 0 ) or ( z = -2y ). Substituting ( z ) into the other equation leads to a system that can be solved for ( x ) and ( y ). However, without numerical values or additional equations, we cannot find unique solutions for ( x, y, ) and ( z ).
3y z 2y 3z15?
The question is not clear.
Simplify 2x plus 6 2y plus 3y?
-4(7x-3y-z)-(-6)(9x-z+2)
What is the x- value of x-2y plus z equals -9 3y-2z equals 4 2x plus y plus 5z equals -5?
x-(x-2y)+z=-9 3y-2z=4 2x+y+5z=-5 x-(x-2y)+z=-9 --distribute negative through bracket--> x-x+2y+z=-9 x-x+2y+z=-9 --combine like terms (x)--> 2y+z=-9 2y+z=-9 --isolate z--> z=-9-2y substitute z into second equation: 3y-2(-9-2y)=4 --multiply -2 through bracket--> 3y+18+4y=4 3y+18+4y=4 --subtract 18 from both sides--> 3y+4y=-14 3y+4y=-14 --combine like terms--> 7y=-14 7y=-14 --divide both sides by 7--> y=-2 Substitute value of y into simplified first equation: z=-9-2(-2) --multiply through the bracket--> z=-9+4 z=-9+4 --combine like terms--> z=-5 Substitute values of y and z into third equation: 2x+(-2)+5(-5)=-5 --multiply through brackets--> 2x-2-25=-5 2x-2-25=-5 --combine like terms--> 2x-27=-5 2x-27=-5 --add 27 to both sides--> 2x=22 2x=22 --divide both sides by 2--> x=11 x=11, y=-2, z=-5
If 2Y plus 3 equals 11 what is the value of Y?
If: 2Y+3 = 11 then the value of Y is 4
What is the minimum value of 2x plus 2y in the feasible region?
2x+2y
What is the value of y in 2y-10 equals to 8?
If: 2y-10 = 8 Then: y = 9
3x 2y z 6 4x - 2y - z 1 2x 5x - 3z 4?
To answer this question we would need to know the signs that go in between the numbers. For example if it was addition, multiplication, or an exponent.
What is the value of 5y-2y?
7
Simplify 2y plus y plus 3z-z?
3y+2z
