2_x_ + 2(x – 4) = 45
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It is: 12 units in length
The length is usually taken to be the longer of the two sides of a rectangle. In this case, therefore, the length is 36 metres.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
Let the length be x+4 and the width be x:- Form a quadratic equation: (x+4)*x = 45 => x^2 +4x -45 = 0 Solving the equation: x has a positive value of 5 Therefore length is 5+4 = 9 feet and width = 5 feet Check: 9 times 5 = 45 square feet
if you are trying to find the area then: width=x length=y y=3+x xy=area 3+x*x=area